Principles of Foundation Engineering (MindTap Course List)
8th Edition
ISBN: 9781305081550
Author: Braja M. Das
Publisher: Cengage Learning
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Chapter 5, Problem 5.3P
Refer to Figure 5.2. Given: B = L = 1.75 m, Df = 1 m, H = 1.75 m, γ = 17 kN/m3, c′ = 0, and ϕ′ = 30°. Using Eq. (5.6) and FS = 4, determine the gross allowable load the foundation can carry.
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A column foundation (Figure P4.5) is 3 m x 2 m in plan. Given: Df = 1.5 m, Φ' = 25°, c' = 70 kN/m2. Using Eq. (4.26) and FS = 3, determine the net allowable load [see Eq. (4.22)] the foundation could carry.
A continuous foundation with a width of 1 m is located on a slope made of clay soil. Refer to Figure 5.19 and let Df = 1 m, H = 4 m, b = 2 m, γ = 16.8 kN/m3, c = cu = 68 kN/m2, Φ= 0, and β = 60°.a. Determine the allowable bearing capacity of the foundation. Let FS = 3.b. Plot a graph of the ultimate bearing capacity qu if b is changed from 0 to 6 m.
Q6. A column foundation (Figure below) is 3 m X 2 m in plan. Given: De = 1.5 m, o = 25°, c=
70 kN/m . Terzaghi's equation and assume general shear failure in soil and FS = 3, determine
the net alowable koad.
y = 17 kN/m
1.5 m
3 m x 2 m
Yat = 19.5 kN/m
Groundwater level
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- Refer to Figure 5.2 and consider a rectangular foundation. Given: B = 1.5 m, L = 2.5 m, Df = 1.2 m, H = 0.9 m, Φ' = 40º, c' = 0, and γ = 17 kN/m3. Using a factor of safety of 3, determine the gross allowable load the foundation can carry. Use Eq. (5.3).arrow_forwardQ 12.9arrow_forwardRefer to Figure 5.2. Given: B = L = 1.75 m, Df = 1 m, H = 1.75 m, γ = 17 kN/m3, c' = 0, and Φ' = 30º. Using Eq. (5.6) and FS = 4, determine the gross allowable load the foundation can carry.arrow_forward
- 3. A square foundation is constructed in a soil deposit as shown in the figure below. Assume that the groundwater table is 6 meters below the foundation. The applied load on the shallow square foundation makes an angle of 10° with the vertical. Use FS = 3 and determine the allowable load. (Use general bearing capacity equation.) 6m 4 m y = 17.5 kN/m³ ' = 33° c' = 20 kN/m² Ysat = 20k N/m³ Groundwater tablearrow_forwardAn eccentrically loaded continuous foundation is shown in Figure P6.18. Determine the ultimate load Qu per unit length that the foundation can carry. Use the reduction factor method [Eq. (6.67)]. 4 ft 2 ft Figure P6.18 Qu 2 ft → -5 ft Y = 105 lb/ft³ Groundwater table Ysat 118 lb/ft³ c' = 0 $' = 35° =arrow_forwardThe applied load on a shallow square foundation makes an angle of 15° with the vertical. Given: B= 1.83 m, D;= 0.91 m, 7 = 18.08 kN/m³, ' = 25°, and d' = 23.96 kN/m?. Use FS= 4 and determine the gross allowable (vertical component) load. Use Eq. (16.9).arrow_forward
- H.Q 1 Consider a rectangular foundation. Given: B = 1.5 m, L = 2.5 m, Df= 1.2 m, H =0.9 m, o' = 40°, c' = 0, and y= 17 kN/m3. Using a factor of safety of 3, determine the gross allowable load the foundation can carry. Use Meyerhof equation.arrow_forwardAn eccentrically loaded continuous foundation is shown in Figure P4.11. Determine the ultimate load Qu per unit length that the foundation can carry. Use the reduction factor method [Eq. (4.63)].arrow_forwardSolve the attached question using Eq. (6.89) attachedarrow_forward
- Pls help.arrow_forwardA square foundation is shown in Figure P6.19. Use FS = 6,and determine the size of the foundation. Use Prakash and Saran's method [Eq. (6.59)].arrow_forwardFor the design of an eccentrically loaded shallow foundation, given the following: Y = 19 kN/m³ Ysat = 20 kN/m³ p' = 30° C' = 8 kN/m² Water Table at 0.5 m depth from GL Soil: 3 Foundation: Size = 1.5 m * 1.5 m Df = 1 m from GL e/B = 0.10 (one way eccentricity) Estimate the ultimate load per unit length of the foundation. using Meyerhof's methodarrow_forward
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