Principles of Foundation Engineering (MindTap Course List)
8th Edition
ISBN: 9781305081550
Author: Braja M. Das
Publisher: Cengage Learning
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Chapter 4, Problem 4.14P
Consider a continuous foundation of width B = 1.4 m on a sand deposit with c′ = 0, ф′ = 38°, and γ = 17.5 kN/m3. The foundation is subjected to an eccentrically inclined load (see Figure 6.33). Given: load eccentricity e = 0.15 m, Df = 1 m, and load inclination β = 18°. Estimate the failure load Qu(ei) per unit length of the foundation
- a. for a partially compensated type of loading [Eq. (6.89)]
- b. for a reinforced type of loading [Eq. (6.90)]
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Chapter 4 Solutions
Principles of Foundation Engineering (MindTap Course List)
Ch. 4 - For the following cases, determine the allowable...Ch. 4 - A square column foundation has to carry a gross...Ch. 4 - Prob. 4.3PCh. 4 - The applied load on a shallow square foundation...Ch. 4 - A column foundation (Figure P6.9) is 3 m × 2 m in...Ch. 4 - Prob. 4.6PCh. 4 - For the design of a shallow foundation, given the...Ch. 4 - An eccentrically loaded foundation is shown in...Ch. 4 - Prob. 4.9PCh. 4 - For an eccentrically loaded continuous foundation...
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- ضهقعفكضكشتبتلتيزذظظؤوروىووؤءظكصحبت٢٨٩٤٨٤ع٣خ٩@@@#&#)@)arrow_forwardA square flexible foundation of width B applies a uniform pressure go to the underlying ground. (a) Determine the vertical stress increase at a depth of 0.5B below the center using Aσ beneath the corner of a uniform rectangular load given by Aσ Variation of Influence Value I m n 0.5 0.6 0.8 1.0 0.2 0.4 0.2 0.01790 0.03280 0.03866 0.04348 0.05042 0.05471 0.4 0.03280 0.06024 0.07111 0.08009 0.09314 0.10129 0.5 0.03866 0.07111 0.08403 0.09473 0.11035 0.12018 0.6 0.04348 0.08009 0.09473 0.10688 0.12474 0.13605 0.8 0.05042 0.09314 0.11035 0.12474 0.14607 0.15978 1.0 0.05471 0.10129 0.12018 0.13605 0.15978 0.17522 (Enter your answer to three significant figures.) Ασ/90 = Activity Frame (b) Determine the vertical stress increase at a depth of 0.5B below the center using the 2 : 1 method equation below. 90 x B x L Aσ = (B+ z) (L+ z) (Enter your answer to three significant figures.) Δσ/90 = (c) Determine the vertical stress increase at a depth of 0.5B below the center using stress isobars in…arrow_forwardNeed help!!!arrow_forward
- 2 A flexible circular area is subjected to a uniformly distributed load of 450 kN/m² (the figure below). The diameter of the load area is 2 m. Estimate the average stress increase (Aσay) below the center of the loaded area between depths of 3 m and 6 m. H₂ 1.0 H₂ B 0.8 CHI HD DV 0.6 C 1.0 1.5 0.4 0.2 6.0 8.0. 10.0 2.0 2.5 3.0 4.0 5.0 H₁ (Enter your answer to two significant figures.) Δσαν τ kN/m² 6arrow_forwardRefer to the figure below. Using the procedure outlined in your textbook, determine the average stress increase in the clay layer below the center of the foundation due to the net foundation load of 45 tons. Use the equations: Aσ = and qo x B x L (B+ z)(L+ z) Aσ av (H2/H₁) Δσι +44 + Δσο net load 6 4:5 ft 10 ft 5ft x 5ft Sand Sand y=100 lb/ft³ Ysat 122 lb/ft³:" Ysat 120 lb/ft³: 0.7 C=0.25 Groundwater table C=0.06 Preconsolidation pressure = 2000 lb/ft² (Enter your answer to three significant figures.) Ασαν = lb/ft²arrow_forwardRefer to the figure below, which shows a flexible rectangular area. Given: B₁ = 4 ft, B₂ = 6 ft, L₁ = 8 ft, and L2 = 10 ft. If the area is subjected to a uniform load of 4100 lb/ft², determine the stress increase at a depth of 10 ft located immediately below point O. Use the table below. T B(1) 3 B(2) 2 L(1) * 4 L2) Table 1 Variation of Influence Value I n m 0.8 0.9 1.0 1.2 1.4 0.1 0.02576 0.02698 0.02794 0.02926 0.03007 0.2 0.05042 0.05283 0.05471 0.05733 0.05894 0.3 0.07308 0.07661 0.07938 0.08323 0.08561 0.4 0.09314 0.09770 0.10129 0.10631 0.10941 0.5 0.11035 0.11584 0.12018 0.12626 0.13003 0.6 0.12474 0.13105 0.13605 0.14309 0.14749 0.7 0.13653 0.14356 0.14914 0.15703 0.16199 0.8 0.14607 0.15371 0.15978 0.16843 0.17389 0.9 0.15371 0.16185 0.16835 0.1766 0.18357 1.0 0.15978 0.16835 0.17522 0.18508 0.19139 1.1 0.16843 0.17766 0.18508 0.19584 0.20278 (Enter your answer to three significant figures.) Aσ = lb/ft²arrow_forward
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- In construction what is the difference in general requirements specific project requirements?arrow_forwardRefer to the figure below. Determine the vertical stress increase Aσ at point A with the values q₁ = 90 kN/m, q2 = 410 kN/m, x₁ = 4m, x2 = 2.5 m, and z = 3 m. Line load = 91 Line load=92 Δε (Enter your answer to three significant figures.) Δατ kN/m²arrow_forwardRefer to the figure below. A strip load of q = 870 lb/ft² is applied over a width B = 36 ft. Determine the increase in vertical stress at point A located z = 15 ft below the surface. Given: x = 27 ft. Use the table below. B q = Load per unit area Aσ A Table 1 Variation of Ao/go with 2z/B and 2x/B 2x/B 2z/B 1.3 1.4 1.5 1.6 0.00 0.000 0.000 0.000 1.7 0.000 0.000 0.10 0.007 0.003 0.002 0.001 0.001 0.20 0.040 0.020 0.011 0.30 0.090 0.052 0.031 0.40 0.141 0.090 0.059 0.040 0.027 0.50 0.185 0.128 0.089 0.063 0.60 0.222 0.163 0.120 0.088 0.70 0.250 0.193 0.80 0.273 0.218 0.007 0.004 0.020 0.013 0.046 0.066 0.148 0.113 0.087 0.173 0.137 0.108 0.90 0.291 0.239 0.195 0.158 0.128 1.00 0.305 0.256 0.214 0.177 0.147 (Enter your answer to three significant figures.) lb/ft² Δοχ =arrow_forward
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