Database Concepts (8th Edition)
8th Edition
ISBN: 9780134601533
Author: David M. Kroenke, David J. Auer, Scott L. Vandenberg, Robert C. Yoder
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Expert Solution & Answer
Chapter 5, Problem 5.18RQ
Explanation of Solution
One-to-many relationship (1:N):
- One-to-many relationship is one of the types of binary relationship that refer to the relationship between two entities which means one parent field or record can be associated with one or more child field or record.
- In a one-to-many relationship (1:N), a parent is a row on the one side of 1:N, while a child is a row on the many side of 1:N which means one parent may contains many child.
Reason for placing the key in the child table which belongs to parent table:
- The parent relation is the “one” and the child relation is “many” in 1:N relationship. An attributes in a parent relation contain only one value.
- If the key belonging to the child was placed in the parent table, then the design should not be used to represent many side of the 1:N relationship...
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
The Horse table has the following columns:
ID - integer, auto increment, primary key
RegisteredName - variable-length string
Breed - variable-length string
Height - decimal number
BirthDate - date
Delete the following rows:
Horse with ID 5
All horses with breed Holsteiner or Paint
All horses born before March 13, 2013
To confirm that the deletes are correct, add the SELECT * FROM HORSE; statement.
Why is Linux popular? What would make someone choose a Linux OS over others? What makes a server? How is a server different from a workstation? What considerations do you have to keep in mind when choosing between physical, hybrid, or virtual server and what are the reasons to choose a virtual installation over the other options?
Objective you will:
1. Implement a Binary Search Tree (BST) from scratch, including the Big Five (Rule of Five)
2. Implement the TreeSort algorithm using a in-order traversal to store sorted elements in a vector.
3. Compare the performance of TreeSort with C++'s std::sort on large datasets.
Part 1: Understanding TreeSort How TreeSort Works TreeSort is a comparison-based sorting algorithm that leverages a Binary Search Tree (BST):
1. Insert all elements into a BST (logically sorting them).
2. Traverse the BST in-order to extract elements in sorted order.
3. Store the sorted elements in a vector.
Time Complexity
Operation Average Case Worst Case (Unbalanced Tree)Insertion 0(1log n) 0 (n)Traversal (Pre-order) 0(n) 0 (n)Overall Complexity 0(n log n) 0(n^2) (degenerated tree)
Note: To improve performance, you could use a…
Chapter 5 Solutions
Database Concepts (8th Edition)
Ch. 5 - Explain how entities are transformed into tables.Ch. 5 - Prob. 5.2RQCh. 5 - Prob. 5.3RQCh. 5 - What is denormalization?Ch. 5 - Prob. 5.5RQCh. 5 - Explain the problems that denormalized tables may...Ch. 5 - Explain how the representation of weak entities...Ch. 5 - Explain how supertype and subtype entities are...Ch. 5 - Prob. 5.9RQCh. 5 - Prob. 5.10RQ
Ch. 5 - Show two different ways to represent the 1:1...Ch. 5 - Prob. 5.12RQCh. 5 - Prob. 5.13RQCh. 5 - Prob. 5.14RQCh. 5 - Prob. 5.15RQCh. 5 - Prob. 5.16RQCh. 5 - For your answer to question 5.15, code an SQL...Ch. 5 - Prob. 5.18RQCh. 5 - Prob. 5.20RQCh. 5 - Prob. 5.21RQCh. 5 - Explain how the terms parent table and child table...Ch. 5 - For your answers to questions 5.20, 5.21, and...Ch. 5 - Prob. 5.24RQCh. 5 - Prob. 5.25RQCh. 5 - Prob. 5.26RQCh. 5 - Prob. 5.27RQCh. 5 - Prob. 5.28RQCh. 5 - Define the three types of recursive binary...Ch. 5 - Prob. 5.30RQCh. 5 - Prob. 5.31RQCh. 5 - Prob. 5.32RQCh. 5 - Prob. 5.33RQCh. 5 - Prob. 5.34RQCh. 5 - Code an SQL statement that creates a table with...
Knowledge Booster
Similar questions
- I need help fixing the minor issue where the text isn't in the proper place, and to ensure that the frequency cutoff is at the right place. My code: % Define frequency range for the plot f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz w = 2 * pi * f; % Angular frequency % Parameters for the filters - let's adjust these to get more reasonable cutoffs R = 1e3; % Resistance in ohms (1 kΩ) C = 1e-6; % Capacitance in farads (1 μF) % For bandpass, we need appropriate L value for desired cutoffs L = 0.1; % Inductance in henries - adjusted for better bandpass response % Calculate cutoff frequencies first to verify they're in desired range f_cutoff_RC = 1 / (2 * pi * R * C); f_resonance = 1 / (2 * pi * sqrt(L * C)); Q_factor = (1/R) * sqrt(L/C); f_lower_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) + 1/(2*Q_factor)); f_upper_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) - 1/(2*Q_factor)); % Transfer functions % Low-pass filter (RC) H_low = 1 ./ (1 + 1i * w *…arrow_forwardMy code is experincing minor issue where the text isn't in the proper place, and to ensure that the frequency cutoff is at the right place. My code: % Define frequency range for the plot f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz w = 2 * pi * f; % Angular frequency % Parameters for the filters - let's adjust these to get more reasonable cutoffs R = 1e3; % Resistance in ohms (1 kΩ) C = 1e-6; % Capacitance in farads (1 μF) % For bandpass, we need appropriate L value for desired cutoffs L = 0.1; % Inductance in henries - adjusted for better bandpass response % Calculate cutoff frequencies first to verify they're in desired range f_cutoff_RC = 1 / (2 * pi * R * C); f_resonance = 1 / (2 * pi * sqrt(L * C)); Q_factor = (1/R) * sqrt(L/C); f_lower_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) + 1/(2*Q_factor)); f_upper_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) - 1/(2*Q_factor)); % Transfer functions % Low-pass filter (RC) H_low = 1 ./ (1 + 1i * w *…arrow_forwardI would like to know the main features about the following three concepts: 1. Default forwarded 2. WINS Server 3. IP Security (IPSec).arrow_forward
- map the following ER diagram into a relational database schema diagram. you should take into account all the constraints in the ER diagram. Underline the primary key of each relation, and show each foreign key as a directed arrow from the referencing attributes (s) to the referenced relation. NOTE: Need relational database schema diagramarrow_forwardWhat is business intelligence? Share the Business intelligence (BI) tools you have used and explain what types of decisions you made.arrow_forwardI need help fixing the minor issue where the text isn't in the proper place, and to ensure that the frequency cutoff is at the right place. My code: % Define frequency range for the plot f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz w = 2 * pi * f; % Angular frequency % Parameters for the filters - let's adjust these to get more reasonable cutoffs R = 1e3; % Resistance in ohms (1 kΩ) C = 1e-6; % Capacitance in farads (1 μF) % For bandpass, we need appropriate L value for desired cutoffs L = 0.1; % Inductance in henries - adjusted for better bandpass response % Calculate cutoff frequencies first to verify they're in desired range f_cutoff_RC = 1 / (2 * pi * R * C); f_resonance = 1 / (2 * pi * sqrt(L * C)); Q_factor = (1/R) * sqrt(L/C); f_lower_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) + 1/(2*Q_factor)); f_upper_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) - 1/(2*Q_factor)); % Transfer functions % Low-pass filter (RC) H_low = 1 ./ (1 + 1i * w *…arrow_forward
- Task 3. i) Compare your results from Tasks 1 and 2. j) Repeat Tasks 1 and 2 for 500 and 5,000 elements. k) Summarize run-time results in the following table: Time/size n String StringBuilder 50 500 5,000arrow_forwardCan you please solve this without AIarrow_forward1. Create a Vehicle.java file. Implement the public Vehicle and Car classes in Vehicle.java, including all the variables and methods in the UMLS. Vehicle - make: String model: String -year: int + Vehicle(String make, String, model, int, year) + getMake(): String + setMake(String make): void + getModel(): String + setModel(String model): void + getYear(): int + set Year(int year): void +toString(): String Car - numDoors: int + numberOfCar: int + Car(String make, String, model, int, year, int numDoors) + getNumDoors(): int + setNumDoors (int num Doors): void + toString(): String 2. Create a CarTest.java file. Implement a public CarTest class with a main method. In the main method, create one Car object and print the object using System.out.println(). Then, print the numberOfCar. Your printing result must follow the example output: make Toyota, model=Camry, year=2022 numDoors=4 1 Hint: You need to modify the toString methods in the Car class and Vehicle class!arrow_forward
- CHATGPT GAVE ME WRONG ANSWER PLEASE HELParrow_forwardHELP CHAT GPT GAVE ME WRONG ANSWER Consider the following implementation of a container that will be used in a concurrent environment. The container is supposed to be used like an indexed array, but provide thread-safe access to elements. struct concurrent_container { // Assume it’s called for any new instance soon before it’s ever used void concurrent_container() { init_mutex(&lock); } ~concurrent_container() { destroy_mutex(&lock); } // Returns element by its index. int get(int index) { lock.acquire(); if (index < 0 || index >= size) { return -1; } int result = data[index]; lock.release(); return result; } // Sets element by its index. void set(int index, int value) { lock.acquire(); if (index < 0 || index >= size) { resize(size); } data[index] = value; lock.release(); } // Extend maximum capacity of the…arrow_forwardWrite a C program using embedded assembler in which you use your own function to multiply by two without using the product. Tip: Just remember that multiplying by two in binary means shifting the number one place to the left. You can use the sample program from the previous exercise as a basis, which increments a variable. Just replace the INC instruction with SHL.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Database Systems: Design, Implementation, & Manag...Computer ScienceISBN:9781305627482Author:Carlos Coronel, Steven MorrisPublisher:Cengage Learning
Database Systems: Design, Implementation, & Manag...Computer ScienceISBN:9781285196145Author:Steven, Steven Morris, Carlos Coronel, Carlos, Coronel, Carlos; Morris, Carlos Coronel and Steven Morris, Carlos Coronel; Steven Morris, Steven Morris; Carlos CoronelPublisher:Cengage Learning
A Guide to SQLComputer ScienceISBN:9781111527273Author:Philip J. PrattPublisher:Course Technology PtrNp Ms Office 365/Excel 2016 I NtermedComputer ScienceISBN:9781337508841Author:CareyPublisher:Cengage
Database Systems: Design, Implementation, & Manag...
Computer Science
ISBN:9781305627482
Author:Carlos Coronel, Steven Morris
Publisher:Cengage Learning
Database Systems: Design, Implementation, & Manag...
Computer Science
ISBN:9781285196145
Author:Steven, Steven Morris, Carlos Coronel, Carlos, Coronel, Carlos; Morris, Carlos Coronel and Steven Morris, Carlos Coronel; Steven Morris, Steven Morris; Carlos Coronel
Publisher:Cengage Learning
A Guide to SQL
Computer Science
ISBN:9781111527273
Author:Philip J. Pratt
Publisher:Course Technology Ptr
Np Ms Office 365/Excel 2016 I Ntermed
Computer Science
ISBN:9781337508841
Author:Carey
Publisher:Cengage