Database Concepts (8th Edition)
8th Edition
ISBN: 9780134601533
Author: David M. Kroenke, David J. Auer, Scott L. Vandenberg, Robert C. Yoder
Publisher: PEARSON
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Expert Solution & Answer
Chapter 5, Problem 5.18RQ
Explanation of Solution
One-to-many relationship (1:N):
- One-to-many relationship is one of the types of binary relationship that refer to the relationship between two entities which means one parent field or record can be associated with one or more child field or record.
- In a one-to-many relationship (1:N), a parent is a row on the one side of 1:N, while a child is a row on the many side of 1:N which means one parent may contains many child.
Reason for placing the key in the child table which belongs to parent table:
- The parent relation is the “one” and the child relation is “many” in 1:N relationship. An attributes in a parent relation contain only one value.
- If the key belonging to the child was placed in the parent table, then the design should not be used to represent many side of the 1:N relationship...
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Change the following code so that there is always at least one way to get from the left corner to the top right, but the labyrinth is still randomized.
The player starts at the bottom left corner of the labyrinth. He has to get to the top right corner of the labyrinth as fast he can, avoiding a meeting with the evil dragon. Take care that the player and the dragon cannot start off on walls. Also the dragon starts off from a randomly chosen position
public class Labyrinth { private final int size; private final Cell[][] grid;
public Labyrinth(int size) { this.size = size; this.grid = new Cell[size][size]; generateLabyrinth(); }
private void generateLabyrinth() { Random rand = new Random(); for (int i = 0; i < size; i++) { for (int j = 0; j < size; j++) { // Randomly create walls and paths grid[i][j] = new Cell(rand.nextBoolean()); } } // Ensure start and end are…
Change the following code so that it checks the following 3 conditions:
1. there is no space between each cells (imgs)
2. even if it is resized, the components wouldn't disappear
3. The GameGUI JPanel takes all the JFrame space, so that there shouldn't be extra space appearing in the frame other than the game.
Main():
Labyrinth labyrinth = new Labyrinth(10);
Player player = new Player(9, 0); Dragon dragon = new Dragon(9, 9);
JFrame frame = new JFrame("Labyrinth Game"); GameGUI gui = new GameGUI(labyrinth, player, dragon);
frame.add(gui); frame.setSize(600, 600); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); frame.setVisible(true);
public class GameGUI extends JPanel { private final Labyrinth labyrinth; private final Player player; private final Dragon dragon; //labyrinth, player, dragon are just public classes
private final ImageIcon playerIcon = new ImageIcon("data/images/player.png");…
Chapter 5 Solutions
Database Concepts (8th Edition)
Ch. 5 - Explain how entities are transformed into tables.Ch. 5 - Prob. 5.2RQCh. 5 - Prob. 5.3RQCh. 5 - What is denormalization?Ch. 5 - Prob. 5.5RQCh. 5 - Explain the problems that denormalized tables may...Ch. 5 - Explain how the representation of weak entities...Ch. 5 - Explain how supertype and subtype entities are...Ch. 5 - Prob. 5.9RQCh. 5 - Prob. 5.10RQ
Ch. 5 - Show two different ways to represent the 1:1...Ch. 5 - Prob. 5.12RQCh. 5 - Prob. 5.13RQCh. 5 - Prob. 5.14RQCh. 5 - Prob. 5.15RQCh. 5 - Prob. 5.16RQCh. 5 - For your answer to question 5.15, code an SQL...Ch. 5 - Prob. 5.18RQCh. 5 - Prob. 5.20RQCh. 5 - Prob. 5.21RQCh. 5 - Explain how the terms parent table and child table...Ch. 5 - For your answers to questions 5.20, 5.21, and...Ch. 5 - Prob. 5.24RQCh. 5 - Prob. 5.25RQCh. 5 - Prob. 5.26RQCh. 5 - Prob. 5.27RQCh. 5 - Prob. 5.28RQCh. 5 - Define the three types of recursive binary...Ch. 5 - Prob. 5.30RQCh. 5 - Prob. 5.31RQCh. 5 - Prob. 5.32RQCh. 5 - Prob. 5.33RQCh. 5 - Prob. 5.34RQCh. 5 - Code an SQL statement that creates a table with...
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