Explanation Sign conversion: Apply the sign convention for calculating the equations of equilibrium as below. For the horizontal forces equilibrium condition, take the force acting towards right side as positive ( → + ) and the force acting towards left side as negative ( ← − ) . For the vertical forces equilibrium condition, take the upward force as positive ( ↑ + ) and downward force as negative ( ↓ − ) . For moment equilibrium condition, take the clockwise moment as negative and counter clockwise moment as positive. Apply the following sign convention for calculating the axial forces, shear and bending moments. When the portion of the beam considered is left of the section, then the external force acting to the left are considered as positive. When the portion of the beam considered is right of the section, then the external force acting to the right are considered as positive. When the portion of the beam considered is left of the section, then the external force acting upward are considered as positive. When the portion of the beam considered is right of the section, then the external force acting downward are considered as positive. When the portion of the beam considered is left of the section, then the clockwise moments are considered as positive. When the portion of the beam considered is right of the section, then the counterclockwise moments are considered as positive. Calculation: Show the free-body diagram of the entire beam as in Figure 1. Find the horizontal reaction at point C by resolving the horizontal equilibrium. + → ∑ F x = 0 − C x + 10 cos 45 ° = 0 C x = 7.07 k ← Find the vertical reaction at point C by resolving the vertical equilibrium. + ↑ ∑ F y = 0 − 10 sin 45 ° + C y = 0 C y = 7.07 k ↓ Find the moment at point C by taking moment about the point C . + ↺ ∑ M C = 0 − 50 + 10 sin 45 ° ( 24 ) − M C = 0 − 50 + 169.71 − M C = 0 M C = 119.71 k-ft Pass the sections aa and bb at points A and B respectively. Show the sections aa and bb as in Figure 2. Consider section aa : Consider the left side of the section aa for calculation of internal forces. Show the free-body diagram of the left side of the section aa as in Figure 3. Find the axial force at point A by resolving the horizontal equilibrium. + ← ∑ F x = 0 7.07 − Q A = 0 Q A = 7

6th Edition

ISBN: 9781337630931

Author: KASSIMALI, Aslam.

Publisher: Cengage,

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Chapter 5, Problem 4P

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Part F: Progressive activity week 7 Q.F1 Pick the rural location of a project site in Victoria, and its catchment area-not bigger than 25 sqkm, and given the below information, determine the rainfall intensity for ARI 5, 50, 100 year storm event. Show all the details of the procedure. Each student must propose different length of streams and elevations. Use fig below as a sample only. Pt. E-nt 950 200 P: D-40, PC-92.0 300m 300m 000m PL.-02.0 500m HI-MAGO PLA-M 91.00 To be deemed satisfactory the solution must include: Q.F1.1.Choice of catchment location Q.F1.2. A sketch displaying length of stream and elevation Q.F1.3. Catchment's IFD obtained from the Buro of Metheorology for specified ARI Q.F1.4.Calculation of the time of concentration-this must include a detailed determination of the equivalent slope. Q.F1.5.Use must be made of the Bransby-Williams method for the determination of the equivalent slope. Q.F1.6.The graphical display of the estimation of intensities for ARI 5,50, 100…

I need help finding: -The axial deflection pipe in inches. -The lateral deflection of the beam in inches -The total deflection of the beam like structure in inches ?

Chapter 5 Solutions

Structural Analysis

Ch. 5 - Prob. 1P Ch. 5 - Prob. 2P Ch. 5 - Prob. 3P Ch. 5 - Prob. 4P Ch. 5 - Prob. 5P Ch. 5 - Prob. 6P Ch. 5 - Prob. 7P Ch. 5 - Prob. 8P Ch. 5 - Prob. 9P Ch. 5 - Prob. 10P

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Find the axial force, shear, and bending moment at points A and B of the beam.

Solution Summary: The author calculates the axial force, shear, and bending moments at points A and B of the beam.

Find the axial force, shear, and bending moment at points A and B of the beam.

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Chapter 5 Solutions