For a given two 200.0L tanks with the gases helium and hydrogen, the mass of each gas is needed to be determined to produce a pressure of 2.70 atm in its respective tank at 24°C . Concept introduction: By combining the three gaseous laws namely Boyle’s law, Charles’s law and Avogadro’s law a combined gaseous equation is obtained. This combined gaseous equation is called Ideal gas law . According to ideal gas law, PV=nRT Where, P = pressure in atmospheres V= volumes in liters n = number of moles R =universal gas constant ( 0.08206 L ⋅ a t m / K ⋅ m o l ) T = temperature in kelvins By knowing any three of these properties, the state of a gas can be simply identified with applying the ideal gas equation. The mass of a given substance can be calculated by, M a s s i n g r a m = n u m b e r o f m o l e s × g r a m m o l e c u l a r m a s s
For a given two 200.0L tanks with the gases helium and hydrogen, the mass of each gas is needed to be determined to produce a pressure of 2.70 atm in its respective tank at 24°C . Concept introduction: By combining the three gaseous laws namely Boyle’s law, Charles’s law and Avogadro’s law a combined gaseous equation is obtained. This combined gaseous equation is called Ideal gas law . According to ideal gas law, PV=nRT Where, P = pressure in atmospheres V= volumes in liters n = number of moles R =universal gas constant ( 0.08206 L ⋅ a t m / K ⋅ m o l ) T = temperature in kelvins By knowing any three of these properties, the state of a gas can be simply identified with applying the ideal gas equation. The mass of a given substance can be calculated by, M a s s i n g r a m = n u m b e r o f m o l e s × g r a m m o l e c u l a r m a s s
Definition Definition Number of atoms/molecules present in one mole of any substance. Avogadro's number is a constant. Its value is 6.02214076 × 10 23 per mole.
Chapter 5, Problem 49E
Interpretation Introduction
Interpretation: For a given two 200.0L tanks with the gases helium and hydrogen, the mass of each gas is needed to be determined to produce a pressure of 2.70 atm in its respective tank at
24°C.
Concept introduction:
By combining the three gaseous laws namely Boyle’s law, Charles’s law and Avogadro’s law a combined gaseous equation is obtained. This combined gaseous equation is called Ideal gas law.
According to ideal gas law,
PV=nRT
Where,
P = pressure in atmospheres
V= volumes in liters
n = number of moles
R =universal gas constant (
0.08206L⋅atm/K⋅mol)
T = temperature in kelvins
By knowing any three of these properties, the state of a gas can be simply identified with applying the ideal gas equation.
The mass of a given substance can be calculated by,
PQ-10. What is the major product of this reaction?
(A)
(C)
930
Me
HO
O=S=O
O-8-CF,
C
어
Me
H+
OH
270
O
0-5-0
O=S=O
O-S-CF
CF3
2
Predict the major organic product(s) of the following reactions. Include stereochemistry when necessary. Write NR if no reaction, try to explain.
Q2: Explain why epoxides that react in an SN1 manner will not show any stereochemical
inversion in the product.
Q3: Rationalize why Alcohol B will react under the indicated reaction conditions, but Alcohol A
will not.
A
☑
OH
B
OH
PBr3
R-Br
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