(a)
Interpretation:
Interpret formula of Copper(i) iodide.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
Answer to Problem 26CR
The formula of given compound is CuI.
Explanation of Solution
Copper(i) is denoted as Cu+ while iodide denoted as I- and thus formula of given compound is CuI.
(b)
Interpretation:
Interpret formula of Cobaltous chloride.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
Answer to Problem 26CR
The formula of given compound is CoCl2.
Explanation of Solution
Cobalt is present in lower oxidation state such as + 2 and thus formula of given compound is CoCl2.
(c)
Interpretation:
Interpret formula of Silver sulfide.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
Answer to Problem 26CR
The formula of given compound is AgF.
Explanation of Solution
Ag is present in lower oxidation state such as + 1 and thus formula of given compound is AgF.
(d)
Interpretation:
Interpret formula of Mercurous bromide.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
Answer to Problem 26CR
The formula of given compound is HgBr2.
Explanation of Solution
Hg is present in lower oxidation state such as + 2 and thus formula of given compound is HgBr2.
(e)
Interpretation:
Interpret formula of Mercuric oxide.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
Answer to Problem 26CR
The formula of given compound is Hg2 O3.
Explanation of Solution
Hg is present in higher oxidation state such as + 3 and thus formula of given compound is Hg2 O3.
(f)
Interpretation:
Interpret formula of Chromium (iii) sulfide.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
Answer to Problem 26CR
The formula of given compound is Cr2 S3.
Explanation of Solution
Cr is present in higher oxidation state such as + 3 and thus formula of given compound is Cr2 S3.
(g)
Interpretation:
Interpret formula of Plumbic oxide.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
Answer to Problem 26CR
The formula of given compound is PbO2.
Explanation of Solution
Pb is present in higher oxidation state such as + 4 and thus formula of given compound is PbO2.
(h)
Interpretation:
Interpret formula of Potassium nitride.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
Answer to Problem 26CR
The formula of given compound is K3 N.
Explanation of Solution
N is present in oxidation state such as -3 and thus formula of given compound is K3 N.
(i)
Interpretation:
Interpret formula of Stannous fluoride.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
Answer to Problem 26CR
The formula of given compound is SnF2.
Explanation of Solution
Sn2 + is present in lower oxidation state such as + 2 and thus formula of given compound is SnF2.
(j)
Interpretation:
Interpret formula of Ferric oxide.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
Answer to Problem 26CR
The formula of given compound is Fe2 O3.
Explanation of Solution
Fe is present in higher oxidation state such as + 3 and thus formula of given compound is Fe2 O3.
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Chapter 5 Solutions
Bundle: Introductory Chemistry: A Foundation, 8th + OWLv2 6-Months Printed Access Card
- Examine the reaction below. Highlight all bonds that have broken in the reactant. Br H H₂C-C- -H 5 H-C-H H-C-H BIE 们 OH H H H₂C-C= H-C-H H-C-Harrow_forwardClassify each of the following as either a substitution, elimination, or addition reaction. CH3 CH3 CH2=CH₂ CH2=C-CH2-OH + Br₂ Br-CH2-C -CH₂-OH Br CH,CH3 CH3-C-CH-CH2-CH3 он ° CH₂ HO C-C-CH3 + NH3 CH₂ он CH3-CH-O-CH3 O-CH3 CH3-C-CH3 + H₂O O-CH3 CH3CH₂ H + H₂O CH3-C=C-CH2-CH3 • CHI Δ Å CH CH3 H+ CH3 C-H + HO-CH3 H" Q-CH₂ CH3-C-CH3 + HO-CH3 OH O substitution O elimination addition substitution O elimination addition O substitution elimination addition O substitution O elimination addition substitution O elimination 00 additionarrow_forwardSearch 5:45 PM Sun Dec 15 Quiz 9 ... ล 25%0 A Done Quiz #9 = Name: Draw the major products of the following. Show Stereochemistry when applicable: 1. OsO4 A 2. NaHSO 3, H 20 Cl₂ ➤ C H2, Pd/C E HBr 1. Hg(OAc) 2, H₂O 2. NaBH 4 Ꭰ KI, H3PO4 F KMnO4, H3O+ KMnO4, H2O G H HBr Br2 J CH2N2 ➤ K CH2I2, Zn(Cu) Cl2, CH3OH C 1. 03 2. Zn, H3O+ HCI 1. BH 3 N M 2. NaOH, H 202 KMnO4, NaOH H₂O P Br2, H2O R 1. BH 3 2. NaOH, H 202 Cl2, CH3CH2OH Tarrow_forward
- Select the stronger base: H-CEN equally basic H H H H-C-N H Select the stronger acid: Select the stronger base: Select the stronger base: H -H equally acidic о equally basic NH equally basic оarrow_forwardClassify each of the following as either a substitution, elimination, or addition reaction. CH3 CH3 CH3-CH-CH2-C-CH3 + Br₂ CH3 CH3 CH3 CH3-C-CH2-C-CH3 + HBr substitution ○ elimination Br CH3 CHI CHO CHA HO CH он Cl CH3-CH2-CH-CH2-CH3 CH₂ DBU H* - CHI CHO CH3 + H2O Ӧ CH3 CH3-CH2-CH=CH-CH3 + HCI OH Pd/C CH3 CH3-CH-CH2-C-CH3 CH3 H C-CH2-CH3 + HO-CH3 addition substitution elimination ○ addition ○ substitution ○ elimination O addition substitution O elimination addition substitution O elimination addition CH3 C-CH3 + H2 CH3 CH3-O-CH-CH2-CH3 Онarrow_forward=> (8 pts) Use retrosynthetic analysis (that is, use retrosynthetic arrows as was done in class) to suggest a synthesis route for the transformation shown below. Sear bonsarrow_forward
- d) 1. Complete the following reactions; all reactions are at room temperature. No heat is involved here. Show Major product only. Indicate the type of mechanism: SN1 or SN2. (1 pt each) a) Br + b) Br e) OH CH3DH + H20 он HCJ Zn Cl₂ OH + HCI 20 C12 + H-Brarrow_forwardWhat is the IUPAC name for the compound shown? LOH IUPAC name: BIU X2 x²arrow_forwardDon't used Ai solutionarrow_forward
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