Bundle: Introductory Chemistry: A Foundation, 8th + OWLv2 6-Months Printed Access Card
Bundle: Introductory Chemistry: A Foundation, 8th + OWLv2 6-Months Printed Access Card
8th Edition
ISBN: 9781305367333
Author: Steven S. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
Question
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Chapter 5, Problem 26CR
Interpretation Introduction

(a)

Interpretation:

Interpret formula of Copper(i) iodide.

Concept Introduction:

Binary ionic compound is the species contains two ions in the compound to form a chemical species.

The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.

For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.

Expert Solution
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Answer to Problem 26CR

The formula of given compound is CuI.

Explanation of Solution

Copper(i) is denoted as Cu+ while iodide denoted as I- and thus formula of given compound is CuI.

Interpretation Introduction

(b)

Interpretation:

Interpret formula of Cobaltous chloride.

Concept Introduction:

Binary ionic compound is the species contains two ions in the compound to form a chemical species.

The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.

For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.

Expert Solution
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Answer to Problem 26CR

The formula of given compound is CoCl2.

Explanation of Solution

Cobalt is present in lower oxidation state such as + 2 and thus formula of given compound is CoCl2.

Interpretation Introduction

(c)

Interpretation:

Interpret formula of Silver sulfide.

Concept Introduction:

Binary ionic compound is the species contains two ions in the compound to form a chemical species.

The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.

For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.

Expert Solution
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Answer to Problem 26CR

The formula of given compound is AgF.

Explanation of Solution

Ag is present in lower oxidation state such as + 1 and thus formula of given compound is AgF.

Interpretation Introduction

(d)

Interpretation:

Interpret formula of Mercurous bromide.

Concept Introduction:

Binary ionic compound is the species contains two ions in the compound to form a chemical species.

The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.

For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.

Expert Solution
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Answer to Problem 26CR

The formula of given compound is HgBr2.

Explanation of Solution

Hg is present in lower oxidation state such as + 2 and thus formula of given compound is HgBr2.

Interpretation Introduction

(e)

Interpretation:

Interpret formula of Mercuric oxide.

Concept Introduction:

Binary ionic compound is the species contains two ions in the compound to form a chemical species.

The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.

For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.

Expert Solution
Check Mark

Answer to Problem 26CR

The formula of given compound is Hg2 O3.

Explanation of Solution

Hg is present in higher oxidation state such as + 3 and thus formula of given compound is Hg2 O3.

Interpretation Introduction

(f)

Interpretation:

Interpret formula of Chromium (iii) sulfide.

Concept Introduction:

Binary ionic compound is the species contains two ions in the compound to form a chemical species.

The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.

For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.

Expert Solution
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Answer to Problem 26CR

The formula of given compound is Cr2 S3.

Explanation of Solution

Cr is present in higher oxidation state such as + 3 and thus formula of given compound is Cr2 S3.

Interpretation Introduction

(g)

Interpretation:

Interpret formula of Plumbic oxide.

Concept Introduction:

Binary ionic compound is the species contains two ions in the compound to form a chemical species.

The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.

For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.

Expert Solution
Check Mark

Answer to Problem 26CR

The formula of given compound is PbO2.

Explanation of Solution

Pb is present in higher oxidation state such as + 4 and thus formula of given compound is PbO2.

Interpretation Introduction

(h)

Interpretation:

Interpret formula of Potassium nitride.

Concept Introduction:

Binary ionic compound is the species contains two ions in the compound to form a chemical species.

The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.

For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.

Expert Solution
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Answer to Problem 26CR

The formula of given compound is K3 N.

Explanation of Solution

N is present in oxidation state such as -3 and thus formula of given compound is K3 N.

Interpretation Introduction

(i)

Interpretation:

Interpret formula of Stannous fluoride.

Concept Introduction:

Binary ionic compound is the species contains two ions in the compound to form a chemical species.

The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.

For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.

Expert Solution
Check Mark

Answer to Problem 26CR

The formula of given compound is SnF2.

Explanation of Solution

Sn2 + is present in lower oxidation state such as + 2 and thus formula of given compound is SnF2.

Interpretation Introduction

(j)

Interpretation:

Interpret formula of Ferric oxide.

Concept Introduction:

Binary ionic compound is the species contains two ions in the compound to form a chemical species.

The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.

For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.

Expert Solution
Check Mark

Answer to Problem 26CR

The formula of given compound is Fe2 O3.

Explanation of Solution

Fe is present in higher oxidation state such as + 3 and thus formula of given compound is Fe2 O3.

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Chapter 5 Solutions

Bundle: Introductory Chemistry: A Foundation, 8th + OWLv2 6-Months Printed Access Card

Ch. 5.2 - Exercise 5.1 Name the following compounds....Ch. 5.2 - Prob. 1CTCh. 5.2 - Exercise 5.2 Give the names of the following...Ch. 5.3 - Exercise 5.3 Name the following compounds....Ch. 5.3 - Exercise 5.4 Name the following compounds....Ch. 5.4 - Exercise 5.5 Name the following binary compounds....Ch. 5.5 - Exercise 5.6 Name each of the following compounds....Ch. 5.5 - Exercise 5.7 Name the following compounds....Ch. 5.7 - Prob. 1CTCh. 5.7 - Prob. 5.8SC
Ch. 5 - In some cases the Roman numeral in a name is the...Ch. 5 - Prob. 2ALQCh. 5 - The formulas MgO and CO look very similar. What is...Ch. 5 - Explain how to use the periodic table to determine...Ch. 5 - Prob. 5ALQCh. 5 - Prob. 6ALQCh. 5 - Name each of the following compounds. SO5 P2S5Ch. 5 - Why do we callBa(NO3)2 barium nitrate hut...Ch. 5 - What is the difference between sulfuric acid and...Ch. 5 - The “Chemistry in Focus” segment Sugar of Lead...Ch. 5 - Prob. 2QAPCh. 5 - Prob. 3QAPCh. 5 - Prob. 4QAPCh. 5 - Prob. 5QAPCh. 5 - Prob. 6QAPCh. 5 - Prob. 7QAPCh. 5 - We indicate the charge of a metallic element that...Ch. 5 - Prob. 9QAPCh. 5 - Prob. 10QAPCh. 5 - Prob. 11QAPCh. 5 - Prob. 12QAPCh. 5 - Prob. 13QAPCh. 5 - Prob. 14QAPCh. 5 - Prob. 15QAPCh. 5 - Prob. 16QAPCh. 5 - Write the name of each of the following binary...Ch. 5 - Write the name for each of the following binary...Ch. 5 - Name each of the following binary compounds, using...Ch. 5 - The formulasNa2O andN2O look very similar. What is...Ch. 5 - Name each of the following binary compounds, using...Ch. 5 - Name each of the following binary compounds, using...Ch. 5 - What is apolyatomicion? Give examples of five...Ch. 5 - Prob. 24QAPCh. 5 - Prob. 25QAPCh. 5 - Prob. 26QAPCh. 5 - Prob. 27QAPCh. 5 - Prob. 28QAPCh. 5 - Prob. 29QAPCh. 5 - Prob. 30QAPCh. 5 - Prob. 31QAPCh. 5 - Prob. 32QAPCh. 5 - Give the name of each of the following polyatomic...Ch. 5 - Prob. 34QAPCh. 5 - Prob. 35QAPCh. 5 - Prob. 36QAPCh. 5 - Give a simple definition of anacid.Ch. 5 - Prob. 38QAPCh. 5 - Prob. 39QAPCh. 5 - Prob. 40QAPCh. 5 - Prob. 41QAPCh. 5 - Prob. 42QAPCh. 5 - Prob. 43QAPCh. 5 - Prob. 44QAPCh. 5 - Prob. 45QAPCh. 5 - Prob. 46QAPCh. 5 - Prob. 47QAPCh. 5 - Prob. 48QAPCh. 5 - Prob. 49QAPCh. 5 - Prob. 50QAPCh. 5 - Prob. 51APCh. 5 - Prob. 52APCh. 5 - Prob. 53APCh. 5 - Prob. 54APCh. 5 - Prob. 55APCh. 5 - Prob. 56APCh. 5 - Name the following compounds. Ca(C2H3O2)2 PCl3...Ch. 5 - Prob. 58APCh. 5 - Prob. 59APCh. 5 - Prob. 60APCh. 5 - Most metallic elements formoxides, and often the...Ch. 5 - Consider a hypothetical simple ionDetermine the...Ch. 5 - Prob. 63APCh. 5 - A metal ion with a 2+ charge has 23 electrons and...Ch. 5 - Prob. 65APCh. 5 - Prob. 66APCh. 5 - The noble metals gold, silver, and platinum are...Ch. 5 - Prob. 68APCh. 5 - The elements of Group 7 (fluorine, chlorine,...Ch. 5 - Prob. 70APCh. 5 - Prob. 71APCh. 5 - An ion with one less electron than it has protons...Ch. 5 - An atom that has lost three electrons will have a...Ch. 5 - An ion with two more electrons than it has protons...Ch. 5 - For each of the negative ions listed in column 1,...Ch. 5 - For each of the following processes that show the...Ch. 5 - For each of the following atomic numbers, use the...Ch. 5 - For the following pairs of ions, use the principle...Ch. 5 - Prob. 79APCh. 5 - Prob. 80APCh. 5 - Prob. 81APCh. 5 - Prob. 82APCh. 5 - Prob. 83APCh. 5 - Name each of the following compounds....Ch. 5 - Prob. 85APCh. 5 - Prob. 86APCh. 5 - Write the foḿu1a for each of the following...Ch. 5 - Give the name of each of the following polyatomic...Ch. 5 - Prob. 89APCh. 5 - Prob. 90APCh. 5 - Prob. 91APCh. 5 - Prob. 92APCh. 5 - Prob. 93APCh. 5 - Complete the following table to predict whether...Ch. 5 - Prob. 95CPCh. 5 - Prob. 96CPCh. 5 - Prob. 97CPCh. 5 - Prob. 98CPCh. 5 - Prob. 1CRCh. 5 - Prob. 2CRCh. 5 - Prob. 3CRCh. 5 - Without consulting your textbook or notes, state...Ch. 5 - Prob. 5CRCh. 5 - What is meant by anuclear atom? Describe the...Ch. 5 - Prob. 7CRCh. 5 - Prob. 8CRCh. 5 - Prob. 9CRCh. 5 - Are most elements found in nature in the elemental...Ch. 5 - What are bus? How are ions formed from atoms? Do...Ch. 5 - Prob. 12CRCh. 5 - Prob. 13CRCh. 5 - Prob. 14CRCh. 5 - Prob. 15CRCh. 5 - Prob. 16CRCh. 5 - Prob. 17CRCh. 5 - Prob. 18CRCh. 5 - Prob. 19CRCh. 5 - Prob. 20CRCh. 5 - Prob. 21CRCh. 5 - How many electrons, protons, and neutrons are...Ch. 5 - What simple ion does each of the following...Ch. 5 - Prob. 24CRCh. 5 - Prob. 25CRCh. 5 - Prob. 26CRCh. 5 - Prob. 27CRCh. 5 - Prob. 28CRCh. 5 - Prob. 29CRCh. 5 - Prob. 30CRCh. 5 - Prob. 31CR
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