Bundle: Introductory Chemistry: A Foundation, 8th + OWLv2 6-Months Printed Access Card
Bundle: Introductory Chemistry: A Foundation, 8th + OWLv2 6-Months Printed Access Card
8th Edition
ISBN: 9781305367333
Author: Steven S. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Chapter 5, Problem 24CR
Interpretation Introduction

(a)

Interpretation:

To determine the number of proton and electron of the ionic species Mg2+.

Concept Introduction:

Ions are formed by loss or gain of an electron. If an atom gain the electron it will carry positive charge and if it lose the electron it will carry the positive charge. The electron present in the outermost shell of an atom is mostly responsible for formation of ions. If the number of proton is less than number of electron the species is anionic and if the number of proton is higher than number of electron the species if cationic.

Expert Solution
Check Mark

Answer to Problem 24CR

The number of proton and electron of Mg2 + species is 12 and 10 respectively.

Explanation of Solution

Atomic number of an ionic species represents the number of proton so, number of proton of Mg2 + is 12 and the number of electron of cationic species is the difference of number of proton and charge given. Number of electron = 12-2 = 10.

Interpretation Introduction

(b)

Interpretation:

To determine the number of proton and electron of the ionic species Fe2+.

Concept Introduction:

Ions are formed by loss or gain of an electron. If an atom gain the electron it will carry positive charge and if it lose the electron it will carry the positive charge. The electron present in the outermost shell of an atom is mostly responsible for formation of ions. If the number of proton is less than number of electron the species is anionic and if the number of proton is higher than number of electron the species if cationic.

Expert Solution
Check Mark

Answer to Problem 24CR

The number of proton and electron of Fe2 + species is 26 and 24 respectively.

Explanation of Solution

Atomic number of an ionic species represents the number of proton so, number of proton of Fe2 + is 26 and the number of electron of cationic species is the difference of number of proton and charge given. Number of electron = 26-2 = 24.

Interpretation Introduction

(c)

Interpretation:

To determine the number of proton and electron of the ionic species Fe3+.

Concept Introduction:

Ions are formed by loss or gain of an electron. If an atom gain the electron it will carry positive charge and if it lose the electron it will carry the positive charge. The electron present in the outermost shell of an atom is mostly responsible for formation of ions. If the number of proton is less than number of electron the species is anionic and if the number of proton is higher than number of electron the species if cationic.

Expert Solution
Check Mark

Answer to Problem 24CR

The number of proton and electron of Fe3 + species is 26 and 23 respectively.

Explanation of Solution

Atomic number of an ionic species represents the number of proton so, number of proton of Fe2 + is 26 and the number of electron of cationic species is the difference of number of proton and charge given. Number of electron = 26-3 = 23.

Interpretation Introduction

(d)

Interpretation:

To determine the number of proton and electron of the ionic species F-.

Concept Introduction:

Ions are formed by loss or gain of an electron. If an atom gain the electron it will carry positive charge and if it lose the electron it will carry the positive charge. The electron present in the outermost shell of an atom is mostly responsible for formation of ions. If the number of proton is less than number of electron the species is anionic and if the number of proton is higher than number of electron the species if cationic.

Expert Solution
Check Mark

Answer to Problem 24CR

The number of proton and electron of F- species is 9 and 10 respectively.

Explanation of Solution

Atomic number of an ionic species represents the number of proton so, number of proton of Mg2 + is 9 and the number of electron of cationic species is the addition of number of proton and charge given. Number of electron = 9+1 = 10.

Interpretation Introduction

(e)

Interpretation:

To determine the number of proton and electron of the ionic species Ni2+.

Concept Introduction:

Ions are formed by loss or gain of an electron. If an atom gain the electron it will carry positive charge and if it lose the electron it will carry the positive charge. The electron present in the outermost shell of an atom is mostly responsible for formation of ions. If the number of proton is less than number of electron the species is anionic and if the number of proton is higher than number of electron the species if cationic.

Expert Solution
Check Mark

Answer to Problem 24CR

The number of proton and electron of Ni2 + species is 28 and 26 respectively.

Explanation of Solution

Atomic number of an ionic species represents the number of proton so, number of proton of Ni2 + is 28 and the number of electron of cationic species is the difference of number of proton and charge given. Number of electron = 28-2 = 26.

Interpretation Introduction

(f)

Interpretation:

To determine the number of proton and electron of the ionic species Zn2+.

Concept Introduction:

Ions are formed by loss or gain of an electron. If an atom gain the electron it will carry positive charge and if it lose the electron it will carry the positive charge. The electron present in the outermost shell of an atom is mostly responsible for formation of ions. If the number of proton is less than number of electron the species is anionic and if the number of proton is higher than number of electron the species if cationic.

Expert Solution
Check Mark

Answer to Problem 24CR

The number of proton and electron of Zn2 + species is 30 and 28 respectively.

Explanation of Solution

Atomic number of an ionic species represents the number of proton so, number of proton of Zn2 + is 30 and the number of electron of cationic species is the difference of number of proton and charge given. Number of electron = 30-2 = 28.

Interpretation Introduction

(g)

Interpretation:

To determine the number of proton and electron of the ionic species Co3+.

Concept Introduction:

Ions are formed by loss or gain of an electron. If an atom gain the electron it will carry positive charge and if it lose the electron it will carry the positive charge. The electron present in the outermost shell of an atom is mostly responsible for formation of ions. If the number of proton is less than number of electron the species is anionic and if the number of proton is higher than number of electron the species if cationic.

Expert Solution
Check Mark

Answer to Problem 24CR

The number of proton and electron of Co3 + species is 27 and 24 respectively.

Explanation of Solution

Atomic number of an ionic species represents the number of proton so, number of proton of Co3 + is 27 and the number of electron of cationic species is the difference of number of proton and charge given. Number of electron = 27-3 = 24.

Interpretation Introduction

(h)

Interpretation:

To determine the number of proton and electron of the ionic species N3-.

Concept Introduction:

Ions are formed by loss or gain of an electron. If an atom gain the electron it will carry positive charge and if it lose the electron it will carry the positive charge. The electron present in the outermost shell of an atom is mostly responsible for formation of ions. If the number of proton is less than number of electron the species is anionic and if the number of proton is higher than number of electron the species if cationic.

Expert Solution
Check Mark

Answer to Problem 24CR

The number of proton and electron of N3 - species is 7 and 10 respectively.

Explanation of Solution

Atomic number of an ionic species represents the number of proton so, number of proton of N3 - is 7 and the number of electron of cationic species is the addition of number of proton and charge given. Number of electron = 7+3 = 10.

Interpretation Introduction

(i)

Interpretation:

To determine the number of proton and electron of the ionic species S2-.

Concept Introduction:

Ions are formed by loss or gain of an electron. If an atom gain the electron it will carry positive charge and if it lose the electron it will carry the positive charge. The electron present in the outermost shell of an atom is mostly responsible for formation of ions. If the number of proton is less than number of electron the species is anionic and if the number of proton is higher than number of electron the species if cationic.

Expert Solution
Check Mark

Answer to Problem 24CR

The number of proton and electron of S2 - species is 16 and 18 respectively.

Explanation of Solution

Atomic number of an ionic species represents the number of proton so, number of proton of S2 - is 16 and the number of electron of cationic species is the addition of number of proton and charge given. Number of electron = 16+2 = 18.

Interpretation Introduction

(j)

Interpretation:

To determine the number of proton and electron of the ionic species Rb+.

Concept Introduction:

Ions are formed by loss or gain of an electron. If an atom gain the electron it will carry positive charge and if it lose the electron it will carry the positive charge. The electron present in the outermost shell of an atom is mostly responsible for formation of ions. If the number of proton is less than number of electron the species is anionic and if the number of proton is higher than number of electron the species if cationic.

Expert Solution
Check Mark

Answer to Problem 24CR

The number of proton and electron of Rb+ species is 37and 36 respectively.

Explanation of Solution

Atomic number of an ionic species represents the number of proton so, number of proton of Rb+ is 37 and the number of electron of cationic species is the difference of number of proton and charge given. Number of electron = 37-1=36.

Interpretation Introduction

(k)

Interpretation:

To determine the number of proton and electron of the ionic species Se2-.

Concept Introduction:

Ions are formed by loss or gain of an electron. If an atom gain the electron it will carry positive charge and if it lose the electron it will carry the positive charge. The electron present in the outermost shell of an atom is mostly responsible for formation of ions. If the number of proton is less than number of electron the species is anionic and if the number of proton is higher than number of electron the species if cationic.

Expert Solution
Check Mark

Answer to Problem 24CR

The number of proton and electron of Se2 - species is 34 and 36 respectively.

Explanation of Solution

Atomic number of an ionic species represents the number of proton so, number of proton of Se2 - is 34 and the number of electron of cationic species is the addition of number of proton and charge given. Number of electron = 34+2 = 36.

Interpretation Introduction

(l)

Interpretation:

To determine the number of proton and electron of the ionic species K+.

Concept Introduction:

Ions are formed by loss or gain of an electron. If an atom gain the electron it will carry positive charge and if it lose the electron it will carry the positive charge. The electron present in the outermost shell of an atom is mostly responsible for formation of ions. If the number of proton is less than number of electron the species is anionic and if the number of proton is higher than number of electron the species if cationic.

Expert Solution
Check Mark

Answer to Problem 24CR

The number of proton and electron of K+ species is 19 and 18 respectively.

Explanation of Solution

Atomic number of an ionic species represents the number of proton so, number of proton of K+ is 19 and the number of electron of cationic species is the difference of number of proton and charge given. Number of electron = 19-1 = 18.

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Chapter 5 Solutions

Bundle: Introductory Chemistry: A Foundation, 8th + OWLv2 6-Months Printed Access Card

Ch. 5 - In some cases the Roman numeral in a name is the...Ch. 5 - Prob. 2ALQCh. 5 - The formulas MgO and CO look very similar. What is...Ch. 5 - Explain how to use the periodic table to determine...Ch. 5 - Prob. 5ALQCh. 5 - Prob. 6ALQCh. 5 - Name each of the following compounds. SO5 P2S5Ch. 5 - Why do we callBa(NO3)2 barium nitrate hut...Ch. 5 - What is the difference between sulfuric acid and...Ch. 5 - The “Chemistry in Focus” segment Sugar of Lead...Ch. 5 - Prob. 2QAPCh. 5 - Prob. 3QAPCh. 5 - Prob. 4QAPCh. 5 - Prob. 5QAPCh. 5 - Prob. 6QAPCh. 5 - Prob. 7QAPCh. 5 - We indicate the charge of a metallic element that...Ch. 5 - Prob. 9QAPCh. 5 - Prob. 10QAPCh. 5 - Prob. 11QAPCh. 5 - Prob. 12QAPCh. 5 - Prob. 13QAPCh. 5 - Prob. 14QAPCh. 5 - Prob. 15QAPCh. 5 - Prob. 16QAPCh. 5 - Write the name of each of the following binary...Ch. 5 - Write the name for each of the following binary...Ch. 5 - Name each of the following binary compounds, using...Ch. 5 - The formulasNa2O andN2O look very similar. What is...Ch. 5 - Name each of the following binary compounds, using...Ch. 5 - Name each of the following binary compounds, using...Ch. 5 - What is apolyatomicion? Give examples of five...Ch. 5 - Prob. 24QAPCh. 5 - Prob. 25QAPCh. 5 - Prob. 26QAPCh. 5 - Prob. 27QAPCh. 5 - Prob. 28QAPCh. 5 - Prob. 29QAPCh. 5 - Prob. 30QAPCh. 5 - Prob. 31QAPCh. 5 - Prob. 32QAPCh. 5 - Give the name of each of the following polyatomic...Ch. 5 - Prob. 34QAPCh. 5 - Prob. 35QAPCh. 5 - Prob. 36QAPCh. 5 - Give a simple definition of anacid.Ch. 5 - Prob. 38QAPCh. 5 - Prob. 39QAPCh. 5 - Prob. 40QAPCh. 5 - Prob. 41QAPCh. 5 - Prob. 42QAPCh. 5 - Prob. 43QAPCh. 5 - Prob. 44QAPCh. 5 - Prob. 45QAPCh. 5 - Prob. 46QAPCh. 5 - Prob. 47QAPCh. 5 - Prob. 48QAPCh. 5 - Prob. 49QAPCh. 5 - Prob. 50QAPCh. 5 - Prob. 51APCh. 5 - Prob. 52APCh. 5 - Prob. 53APCh. 5 - Prob. 54APCh. 5 - Prob. 55APCh. 5 - Prob. 56APCh. 5 - Name the following compounds. Ca(C2H3O2)2 PCl3...Ch. 5 - Prob. 58APCh. 5 - Prob. 59APCh. 5 - Prob. 60APCh. 5 - Most metallic elements formoxides, and often the...Ch. 5 - Consider a hypothetical simple ionDetermine the...Ch. 5 - Prob. 63APCh. 5 - A metal ion with a 2+ charge has 23 electrons and...Ch. 5 - Prob. 65APCh. 5 - Prob. 66APCh. 5 - The noble metals gold, silver, and platinum are...Ch. 5 - Prob. 68APCh. 5 - The elements of Group 7 (fluorine, chlorine,...Ch. 5 - Prob. 70APCh. 5 - Prob. 71APCh. 5 - An ion with one less electron than it has protons...Ch. 5 - An atom that has lost three electrons will have a...Ch. 5 - An ion with two more electrons than it has protons...Ch. 5 - For each of the negative ions listed in column 1,...Ch. 5 - For each of the following processes that show the...Ch. 5 - For each of the following atomic numbers, use the...Ch. 5 - For the following pairs of ions, use the principle...Ch. 5 - Prob. 79APCh. 5 - Prob. 80APCh. 5 - Prob. 81APCh. 5 - Prob. 82APCh. 5 - Prob. 83APCh. 5 - Name each of the following compounds....Ch. 5 - Prob. 85APCh. 5 - Prob. 86APCh. 5 - Write the foḿu1a for each of the following...Ch. 5 - Give the name of each of the following polyatomic...Ch. 5 - Prob. 89APCh. 5 - Prob. 90APCh. 5 - Prob. 91APCh. 5 - Prob. 92APCh. 5 - Prob. 93APCh. 5 - Complete the following table to predict whether...Ch. 5 - Prob. 95CPCh. 5 - Prob. 96CPCh. 5 - Prob. 97CPCh. 5 - Prob. 98CPCh. 5 - Prob. 1CRCh. 5 - Prob. 2CRCh. 5 - Prob. 3CRCh. 5 - Without consulting your textbook or notes, state...Ch. 5 - Prob. 5CRCh. 5 - What is meant by anuclear atom? Describe the...Ch. 5 - Prob. 7CRCh. 5 - Prob. 8CRCh. 5 - Prob. 9CRCh. 5 - Are most elements found in nature in the elemental...Ch. 5 - What are bus? How are ions formed from atoms? Do...Ch. 5 - Prob. 12CRCh. 5 - Prob. 13CRCh. 5 - Prob. 14CRCh. 5 - Prob. 15CRCh. 5 - Prob. 16CRCh. 5 - Prob. 17CRCh. 5 - Prob. 18CRCh. 5 - Prob. 19CRCh. 5 - Prob. 20CRCh. 5 - Prob. 21CRCh. 5 - How many electrons, protons, and neutrons are...Ch. 5 - What simple ion does each of the following...Ch. 5 - Prob. 24CRCh. 5 - Prob. 25CRCh. 5 - Prob. 26CRCh. 5 - Prob. 27CRCh. 5 - Prob. 28CRCh. 5 - Prob. 29CRCh. 5 - Prob. 30CRCh. 5 - Prob. 31CR
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