Chapter 5, Problem 25QP

Interpretation Introduction

Interpretation:

The work done for the expansion of gas in a system against given different pressure conditions is to be calculated.

Concept Introduction:

The expansion of gas involves the increase in its volume against constant pressure, known as external pressure.

Expansion of a gas involves work done by the system that is calculated by multiplying the external pressure with the change in volume of the system. It can be represented as:

$w=-P\left(V_2-V_1\right)$

Here, $w$ is the work done, $P$ is the pressure, $V_1$ is the initial volume of gas, and $V_2$ is the final volume of the gas.

The conversion of work done from $\text{L}\cdot \text{atm}$ into $\text{J}$ is done as:

$1\text{L}\cdot \text{atm}=101.3\text{J}$