Concept explainers
What is each compound’s systematic name?
(a)
![Check Mark](/static/check-mark.png)
Interpretation:
The systematic name should be given for the compound.
Concept introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry).IUPAC name consists of three parts, namely Prefix, suffix and root word.
Prefix- Represents the substituent present in the molecule and its position in the root name.
Suffix- Denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc. To add suffix to name a compound, the suffix “-ane” in the parent alkane is replaced by the respective suffix, which corresponds to the functional group present in the given compound. For carboxylic acid, suffix “-oic” will be added, for alcohol, suffix “-ol” will be added and so on
Root word - Represents the longest continuous carbon skeleton of the organic molecule.
Alkenes:
Alkenes are a class of hydrocarbons. The carbon-carbon double bond is called as alkenes and it is also called as olefins.
Explanation of Solution
The name of the compound is given below,
The number of carbon in parent chain is five, hence it is called as pentane, it is in cycle form therefore cyclopentane. The functional group of the given molecule is alkene therefore the suffix “-ane” is replaced with “-ene” indicating the presence of double bond. In the given structure the first and fifth carbon is bonded with methyl group, double bond in first carbon. Therefore the name of the compound is 1, 5- Dimethyl cyclopent-1-ene.
(b)
![Check Mark](/static/check-mark.png)
Interpretation:
The systematic name should be given for the compound.
Concept introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry).IUPAC name consists of three parts, namely Prefix, suffix and root word.
Prefix- Represents the substituent present in the molecule and its position in the root name.
Suffix- Denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc. To add suffix to name a compound, the suffix “-ane” in the parent alkane is replaced by the respective suffix, which corresponds to the functional group present in the given compound. For carboxylic acid, suffix “-oic” will be added, for alcohol, suffix “-ol” will be added and so on
Root word - Represents the longest continuous carbon skeleton of the organic molecule.
Alkenes:
Alkenes are a class of hydrocarbons. The carbon-carbon double bond is called as alkenes and it is also called as olefins.
Explanation of Solution
The name of the compound is given below,
The number of carbon in parent chain is six, hence it is called as hexane, it is in cycle form therefore cyclohexane. The functional group of the given molecule is alkene therefore the suffix “-ane” is replaced with “-ene” indicating the presence of double bond. In the given structure the fourth carbon is bonded with methyl group, double bond in first carbon. Therefore the name of the compound is 4-Methyl cyclohex-1-ene.
(c)
![Check Mark](/static/check-mark.png)
Interpretation:
The systematic name should be given for the compound.
Concept Introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry).IUPAC name consists of three parts, namely Prefix, suffix and root word.
Prefix- Represents the substituent present in the molecule and its position in the root name.
Suffix- Denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc. To add suffix to name a compound, the suffix “-ane” in the parent alkane is replaced by the respective suffix, which corresponds to the functional group present in the given compound. For carboxylic acid, suffix “-oic” will be added, for alcohol, suffix “-ol” will be added and so on
Root word - Represents the longest continuous carbon skeleton of the organic molecule.
Alkenes:
Alkenes are a class of hydrocarbons. The carbon-carbon double bond is called as alkenes and it is also called as olefins.
Explanation of Solution
The name of the compound is given below,
The number of carbon in parent chain is six, hence it is called as hexane, it is in cycle form therefore cyclohexane. The functional group of the given molecule is alkene therefore the suffix “-ane” is replaced with “-ene” indicating the presence of double bond. In the given structure the fourth carbon is bonded with methyl group, fifth carbon is bonded with ethyl group, double bond in first carbon. Therefore the name of the compound is 5-ethyl-4-Methyl cyclohex-1-ene.
Want to see more full solutions like this?
Chapter 5 Solutions
EP ESSENTIAL ORG.CHEM.-MOD.MASTERING
- टे Predict the major products of this organic reaction. Be sure to use wedge and dash bonds when necessary, for example to distinguish between different major products. ☐ ☐ : ☐ + NaOH HO 2 Click and drag to start drawing a structure.arrow_forwardShown below are five NMR spectra for five different C6H10O2 compounds. For each spectrum, draw the structure of the compound, and assign the spectrum by labeling H's in your structure (or in a second drawing of the structure) with the chemical shifts of the corresponding signals (which can be estimated to nearest 0.1 ppm). IR information is also provided. As a reminder, a peak near 1700 cm-1 is consistent with the presence of a carbonyl (C=O), and a peak near 3300 cm-1 is consistent with the presence of an O–H. Extra information: For C6H10O2 , there must be either 2 double bonds, or 1 triple bond, or two rings to account for the unsaturation. There is no two rings for this problem. A strong band was observed in the IR at 1717 cm-1arrow_forwardPredict the major products of the organic reaction below. : ☐ + Х ك OH 1. NaH 2. CH₂Br Click and drag to start drawing a structure.arrow_forward
- NG NC 15Show all the steps you would use to synthesize the following products shown below using benzene and any organic reagent 4 carbons or less as your starting material in addition to any inorganic reagents that you have learned. NO 2 NC SO3H NO2 OHarrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forwardShow work...don't give Ai generated solutionarrow_forward
- 1 Please provide an efficient synthesis of the product below from the starting material. Use the starting material as the ONLY source of carbon atoms. Show the synthesis of each compound that would be used in the overall synthesis of the product. [This synthesis uses alkyne and alcohol chemistry.]arrow_forward10- 4000 20 20 30- %Reflectance 60 50- 09 60- 40- Date: Thu Feb 06 17:30:02 2025 (GMT-05:0(UnknownP Scans: 8 Resolution: 2.000 70 70 88 80 3500 3000 2500 90 100 00 Wavenumbers (cm-1) 2000 1500 2983.10 2359.13 1602.52 1584.22 1451.19 1391.87 1367.07 1314.37 1174.34 1070.13 1027.33 1714.16 1269.47 1000 1106.08 1001.14 937.02 873.60 850.20 780.22 686.91 674.38 643.09 617.98 02/06/25 16:38:20arrow_forwardd. Draw arrow-pushing mechanism for an enzymatic retro-aldol reaction of the following hexose. Use B: and/or HA as needed. OH OH سية HO OH OHarrow_forward
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305080485/9781305080485_smallCoverImage.gif)