Chapter 5, Problem 20P

Perform the same computation as in Prob. 5.19, but for the frustrumof a cone, as depicted in Fig. P5.20.Employ the following values for your computation: $r_1=0.5\text{m,}{r}_2=1\text{m,}h=1\text{m,}\rho f=$ frustumdensity $=200$ ${\text{kg/m}}^3$, and ${\rho }_w=\text{ water density}$ ${\text{= 1000 kg/m}}^3$.

Note that the volume of a frustrum is given by

$V=\frac{\pi h}{3}\left(r_1^2+r_2^2+r_1{r}_2\right)$

FIGURE P5.20