The reason why the area under the graph of a positive velocity function gives the total distance that has been travelled.

Answer to Problem 1RWDT
It has been shown why the area under the graph of a positive velocity function gives the total distance that has been travelled.
Explanation of Solution
Given:
An arbitrary graph of a positive velocity function.
Concept used:
Distance travelled is the product of speed and time.
Calculation:
The difference between speed and velocity is that speed does not have a direction and is always positive, while velocity has direction and may be positive or negative.
This implies that a positive velocity function is nothing but a function which denotes the speed.
Now, for each small interval of time, the distance travelled is evaluated by multiplying the small interval of time and the velocity at that small interval of time, which tends to a constant value for sufficiently small intervals of time. Note that this value is nothing but the area of a small vertical strip under the graph.
Adding all such values for subsequent intervals of time, the total distance can be evaluated. On the other hand, geometrically, such a value is nothing but the total area under the graph.
This shows why the area under the graph of a positive velocity function gives the total distance that has been travelled.
Conclusion:
It has been shown why the area under the graph of a positive velocity function gives the total distance that has been travelled.
Want to see more full solutions like this?
Chapter 5 Solutions
Advanced Placement Calculus Graphical Numerical Algebraic Sixth Edition High School Binding Copyright 2020
- DO NOT GIVE THE WRONG ANSWER SHOW ME ALL THE NEEDED STEPS 11: A rectangle has a base that is growing at a rate of 3 inches per second and a height that is shrinking at a rate of one inch per second. When the base is 12 inches and the height is 5 inches, at what rate is the area of the rectangle changing?arrow_forwardplease answer by showing all the dfalowing necessary step DO NOT GIVE ME THE WRONG ANSWER The sides of a cube of ice are melting at a rate of 1 inch per hour. When its volume is 64 cubic inches, at what rate is its volume changing?arrow_forwardSox & Sin (px) dx 0arrow_forward
- 8 L 8 e ipx dxarrow_forwardFind the Taylor polynomial T³(×) for the function f centered at the number a. f(x) = xe-2x a = 0 T3(x) =arrow_forwardFor each graph in Figure 16, determine whether f (1) is larger or smaller than the slope of the secant line between x = 1 and x = 1 + h for h > 0. Explain your reasoningarrow_forward
- Points z1 and z2 are shown on the graph.z1 is at (4 real,6 imaginary), z2 is at (-5 real, 2 imaginary)Part A: Identify the points in standard form and find the distance between them.Part B: Give the complex conjugate of z2 and explain how to find it geometrically.Part C: Find z2 − z1 geometrically and explain your steps.arrow_forwardA polar curve is represented by the equation r1 = 7 + 4cos θ.Part A: What type of limaçon is this curve? Justify your answer using the constants in the equation.Part B: Is the curve symmetrical to the polar axis or the line θ = pi/2 Justify your answer algebraically.Part C: What are the two main differences between the graphs of r1 = 7 + 4cos θ and r2 = 4 + 4cos θ?arrow_forwardA curve, described by x2 + y2 + 8x = 0, has a point A at (−4, 4) on the curve.Part A: What are the polar coordinates of A? Give an exact answer.Part B: What is the polar form of the equation? What type of polar curve is this?Part C: What is the directed distance when Ø = 5pi/6 Give an exact answer.arrow_forward
- New folder 10. Find the area enclosed by the loop of the curve (1- t², t-t³)arrow_forward1. Graph and find the corresponding Cartesian equation for: t X== y = t +1 2 te(-∞, ∞) 42,369 I APR 27 F5 3 MacBook Air stv A Aa T 4 DIIarrow_forwardMiddle School GP... Echo home (1) Addition and su... Google Docs Netflix Netflix New folder 9. Find the area enclosed by x = sin²t, y = cost and the y-axis.arrow_forward
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning





