Concept explainers
To explain: whether the midpoint Rule is always more accurate than the Trapezoidal Rule
Answer to Problem 16RQ
The accuracy of the different approximation methods always depends on the function being approximated
Explanation of Solution
Given information: We have been given Midpoint Rule and Trapezoidal Rule
The midpoint rule approximates the definite integral using rectangular regions whereas
the trapezoidal rule approximates the definite integral using trapezoidal approximations
one rule works better then the other rule. The accuracy of the Rule always depends on the function being
Approximated. For example, make a function which is linear except it has narrow spikes at the mid points of the
Subdivided Intervals. Then the approximating rectangles for the Midpoint Rule will rise up to the level of the spikes,
And be a huge overestimate.
The Trapezoidal Rule basically not count the spikes.
Chapter 5 Solutions
Single Variable Calculus: Concepts and Contexts, Enhanced Edition
- Suppose the number of people who register to attend the Tucson Festival of Books can be modeled by P(t) = k(1.1), where t is the number of days since the registration window opened. Assume k is a positive constant. Which of the following represents how long it will take in days for the number of people who register to double? t = In(1.1) In(2) In(2) t = In(1.1) In(1.1) t = t = t = In(2) - In(k) In(2) In(k) + In(1.1) In(2) - In(k) In(1.1)arrow_forwardUse the method of washers to find the volume of the solid that is obtained when the region between the graphs f(x) = √√2 and g(x) = secx over the interval ≤x≤ is rotated about the x-axis.arrow_forward5 Use the method of disks to find the volume of the solid that is obtained when the region under the curve y = over the interval [4,17] is rotated about the x-axis.arrow_forward
- 3. Use the method of washers to find the volume of the solid that is obtained when the region between the graphs f(x) = √√2 and g(x) = secx over the interval ≤x≤ is rotated about the x-axis.arrow_forward4. Use cylindrical shells to find the volume of the solid generated when the region enclosed by the given curves is revolved about the x-axis. y = √√x, y = 0, y = √√3arrow_forward5 4 3 21 N -5-4-3-2 -1 -2 -3 -4 1 2 3 4 5 -5+ Write an equation for the function graphed above y =arrow_forward
- 6 5 4 3 2 1 -5 -4-3-2-1 1 5 6 -1 23 -2 -3 -4 -5 The graph above is a transformation of the function f(x) = |x| Write an equation for the function graphed above g(x) =arrow_forwardThe graph of y x² is shown on the grid. Graph y = = (x+3)² – 1. +10+ 69 8 7 5 4 9 432 6. 7 8 9 10 1 10 -9 -8 -7 -6 -5 -4 -3 -2 -1 1 2 3 4 5 -2 -3 -4 -5 -6- Clear All Draw:arrow_forwardSketch a graph of f(x) = 2(x − 2)² − 3 4 3 2 1 5 ས་ -5 -4 -3 -2 -1 1 2 3 4 -1 -2 -3 -4 -5+ Clear All Draw:arrow_forward
- 5. Find the arc length of the curve y = 3x³/2 from x = 0 to x = 4.arrow_forward-6 -5 * 10 8 6 4 2 -2 -1 -2 1 2 3 4 5 6 -6 -8 -10- The function graphed above is: Concave up on the interval(s) Concave down on the interval(s) There is an inflection point at:arrow_forward6 5 4 3 2 1 -6 -5 -3 -2 3 -1 -2 -3 -4 -5 The graph above is a transformation of the function x² Write an equation for the function graphed above g(x) =arrow_forward
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning