
Carry out the calculations that lead from Eq. (8) to Eq. (11) in the discussion preceding Problem 4.
ϕ(ε)=J(ˉx+εξ, ˉy+εη)=b∫aF(t, ˉx+εξ,ˉy+εη, ˉx′+εξ′, ˉy′+εη′), (8)
where the perturbation
〈ξ(a),η(a)〉=〈0,0〉 and 〈ξ(b),η(b)〉=〈0,0〉. (9)
Thus, for
ϕ(ε) defined by Eq.
(8), we compute
ϕ′(0)=0,
b∫a{[Fx−Fx′t]ξ+[Fy−Fy′t]η} dt = 0. (10)
Since Eq. (10) must hold for any ξ and η satisfying the conditions (9), we conclude that each factor multiplying ξ and η in the integrand must equal zero,
Fx−Fx′t=0Fy−Fy′t=0. (11)

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