In each of Problems 1 through 26: (a) Find the general solution in terms of real functions. (b) From the roots of the characteristics equation, determine whether each critical point of the corresponding dynamical system is asymptotically stable, stable, or unstable, and classify it as to type. (c) Use the general solution obtained in part (a) to find a two parameter family of trajectories X = x 1 i + x 2 j = y i + y ' j of the corresponding dynamical system. Then sketch by hand, or use a computer, to draw a phase portrait, including any straight-line orbits, from this family of trajectories. y ' ' − 2 y ' − 2 y = 0
In each of Problems 1 through 26: (a) Find the general solution in terms of real functions. (b) From the roots of the characteristics equation, determine whether each critical point of the corresponding dynamical system is asymptotically stable, stable, or unstable, and classify it as to type. (c) Use the general solution obtained in part (a) to find a two parameter family of trajectories X = x 1 i + x 2 j = y i + y ' j of the corresponding dynamical system. Then sketch by hand, or use a computer, to draw a phase portrait, including any straight-line orbits, from this family of trajectories. y ' ' − 2 y ' − 2 y = 0
(a) Find the general solution in terms of real functions.
(b) From the roots of the characteristics equation, determine whether each critical point of the corresponding dynamical system is asymptotically stable, stable, or unstable, and classify it as to type.
(c) Use the general solution obtained in part (a) to find a two parameter family of trajectories
X
=
x
1
i
+
x
2
j
=
y
i
+
y
'
j
of the corresponding dynamical system. Then sketch by hand, or use a computer, to draw a phase portrait, including any straight-line orbits, from this family of trajectories.
In Problems 1-16 the indicated function y₁(x) is a solution of the
given differential equation. Use reduction of order or formula (5), as
instructed, to find a second solution y2(x).
1. y" - 4y' + 4y = 0; yı
=
e2x
The function f is shown below. If g is an antiderivative of f such that g(6) = 2, what is the maximum value of g on the closed interval
[-9,9]?
8
7
6
Сл
5
4
3
1
y
Graph of f
-10 -9 -8 -7 -6 -5 -4 -3 -2 -1
1
23 4
-1
-2
-3
-4
-6
56
-5
-7
-8
LO
5
9
7
8
9
10
x
The function of is shown below. If I is the function defined by g(x) = [* f(t)dt, write the equation of the line tangent to the graph of 9
at x = -3.
g
y
Graph of f
8
7
6
5
4
32
1
x
-10 -9 -8 -7 -6 -5 -4 -3 -2 -1
1
2
3 4
5
6
7
8
9 10
-1
-2
-3
56
-6
-7
-8
Chapter 4 Solutions
Differential Equations: An Introduction To Modern Methods And Applications 3e Binder Ready Version + Wileyplus Registration Card
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