Chapter 4.8, Problem 28PPS

To determine

To Find: The graph of inequality

Answer to Problem 28PPS

No graph

Explanation of Solution

Given:

  $3x^2+12x+36\le 0$

Formula Used:

  $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Calculation:

  $\begin{array}{l}3x^2+12x+36\le 0\\ a=3;\\ b=12;\\ c=36\\ x=\frac{-12\pm \sqrt{{12}^2-4\left(3\right)\left(36\right)}}{6}\\ \Rightarrow x=\frac{-12\pm \sqrt{-288}}{6}\\ \Rightarrow x=\frac{-12\pm 12i\sqrt{2}}{6}\\ \Rightarrow x=\frac{-2\pm 2i\sqrt{2}}{1}\\ \Rightarrow x=-2-2i\sqrt{2}or-2+2i\sqrt{2}\end{array}$

Since there is imaginary roots so no graph