
To find: The y -intercept, the equation of the axis of symmetry, and the coordinate of the vertex of the given function and hence plot the graph.

Answer to Problem 1MCQ
The y -intercept, the equation of the axis of symmetry, and the coordinate of the vertex of the given function are given below.
Explanation of Solution
Given:
The given function is:
f(x)=2x2+8x−3 …(1)
The standard form of parabola when it is symmetry to x-axis is:
(x−h)2=4p(y−k)
Solve the given function to make it perfect square as:
f(x)=2(x2+4x+4−4−32)f(x)=2(x+2)2−11
Further simplified for the y -intercept, the equation of symmetry, and the coordinate of the vertex is as:
To find y -intercept put x=0 in above equation gives:
y-intercept=2(0+2)2−11(put x=0)=−3
The equation of the axis of symmetry is x=−2 .
The coordinate of the vertex is given as:
vertex=(−2,−11)
The graph of the function is given as:
x | 0 | −2 |
f(x) | −3 | −11 |
The above graph is the graph of parabola.
Chapter 4 Solutions
Glencoe Algebra 2 Student Edition C2014
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