Chapter 4.2, Problem 8E

To determine

To solve: the given equation rounds up to nearest tenth.

Answer to Problem 8E

  $x=5$ .

Explanation of Solution

Given:

The given equation is $x^2-10x=-25$ .

Calculation:

The given equation is $x^2-10x+25=0$ .

Now, solve the given equation by factor method. Therefore,

  $\begin{array}{l}{x}^2-10x+25=0\left\{\text{given function}\right\}\\ x^2-5x-5x+25=0\left\{\text{arrange in to the factor form}\right\}\\ x\left(x-5\right)+5\left(x-5\right)=0\{\text{factor} }\\ \left(x-5\right)\left(x-5\right)=0\end{array}$

Therefore,

  $\begin{array}{l}{\left(x-5\right)}^2=0\\ \left(x-5\right)=0\\ x=5\end{array}$

Hence, the value of the given equation rounds up to nearest tenth is $x=5$ .