
To graph: The expression as mentioned in the problem.

Answer to Problem 68SR
The solution of the mentioned expression is (4,8) .
Explanation of Solution
Given information:
The expression mentioned is y=3x−4y=−2x+16 .
Formula used:
We will draw the straight line graph.
Graph:
The graph is drawn on the real numbers of x axis and y axis where graph of y−3x=−4 shows red line and the graph of y+2x=16 shows blue line.
Interpretation:
Consider the expression y=3x−4⇒y−3x=−4.......(i)y=−2x+16⇒y+2x=16......(ii) .
Recall that the above mentioned expression is in linear form.
Therefore there graph will be of straight line.
Now we fix the values of both the equations mentioned above.
Therefore we will take the values x01y10 in both the above mentioned equation than the graph will be as obtained above and the intersection of both the graph will be a solution of the expression y=3x−4⇒y−3x=−4.......(i)y=−2x+16⇒y+2x=16......(ii) .
Therefore the solution is (4,8) .
Chapter 4 Solutions
Glencoe Algebra 2 Student Edition C2014
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