BIOLOGY(LL)-W/ACCESS CODE >CUSTOM<
12th Edition
ISBN: 9781264058167
Author: Raven
Publisher: MCG CUSTOM
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Chapter 47, Problem 4DA
Summary Introduction
To explain: That how would an individual determine how much oxygen was unloaded to the tissues.
Introduction: The oxygen is a colorless, odourless, gaseous element which is essential for respiration because body uses it to burn food molecules. Animals take in the oxygen when inhaling and give off carbon dioxide when exhaling.
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Overview of Transformation Protocol
-Prepare competent bacteria for transformation:
Treat starter E. coli bacteria with CaCl2and Competent Cell Solution (CCS). Store on ice until transformation procedure.
Competent cells are cells that are likely to take up foreign DNA and be transformed. This step increases the likelihood that the E. coli cells will take up the introduced vector and be transformed.
-Transformation procedure:
Obtain two microcentrifuge tubes containing your competent cells. Label one tube +DNA and one -DNA.
Add CaCl2 to both tubes.
Add the transformation mix containing the plasmid DNA to the tube labeled +DNA. Do not add any plasmid DNA to the -DNA tube.
Incubate both tubes on ice for 10 minutes. Then, place both tubes in a 42\deg C water bath for 45 seconds. Replace the tubes in an ice bucket for 2 minutes.
Add recovery broth to both tubes.
Incubate both tubes in a 37 C water bath for 5 minutes.
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1)What is the selectable marker in this experiment? How…
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In oxidase test with Pseudomonas aeruginosa, the cell cultures on the slide turn colorless to be
purple after tetra-methyl-p-phenylenediamine dihydrochloride (TMPD) is added. In the
reaction,
OTMPD is electron acceptor
O cytochrome c is the electron source
oxygen is terminal electron acceptor
OH2 produced is electron donor
Chapter 47 Solutions
BIOLOGY(LL)-W/ACCESS CODE >CUSTOM<
Ch. 47.1 - Prob. 1LOCh. 47.1 - Prob. 2LOCh. 47.1 - Compare evolutionary strategies for maximizing gas...Ch. 47.2 - Prob. 1LOCh. 47.2 - Prob. 2LOCh. 47.3 - Prob. 1LOCh. 47.3 - Prob. 2LOCh. 47.3 - Describe the breathing cycle of birds.Ch. 47.4 - Prob. 1LOCh. 47.4 - Prob. 2LO
Ch. 47.4 - Prob. 3LOCh. 47.5 - Describe the structure of hemoglobin.Ch. 47.5 - Predict hemoglobins oxygen affinity in various...Ch. 47.5 - Prob. 3LOCh. 47 - Prob. 1DACh. 47 - Prob. 2DACh. 47 - Prob. 3DACh. 47 - Prob. 4DACh. 47 - For a given PO2, how does oxyhemoglobin saturation...Ch. 47 - Prob. 1IQCh. 47 - Prob. 2IQCh. 47 - Prob. 1UCh. 47 - Increased efficiency of gas exchange in...Ch. 47 - Prob. 3UCh. 47 - Prob. 4UCh. 47 - Ficks Law of Diffusion states the rate of...Ch. 47 - Prob. 6UCh. 47 - Prob. 7UCh. 47 - Prob. 8UCh. 47 - When you take a deep breath, your stomach moves...Ch. 47 - Marine mammals are able to hold their breath for...Ch. 47 - Countercurrent flow systems do not occur in lungs...Ch. 47 - Respiratory organs of invertebrates and...Ch. 47 - Prob. 5ACh. 47 - During exercise more oxygen is delivered to the...Ch. 47 - Compare the operation and efficiency of fish gills...Ch. 47 - What happens when, during exercise, the oxygen...Ch. 47 - Explain how bacteria, archaea, protists, and many...
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- Which of the following is a weakness of using 16S rRNA for phylogenetic analyses? It can only go down to the family and genus levels It takes months to complete O Both of the above O None of the abovearrow_forwardAn unrooted tree containing ten unrelated species can become rooted by adding a descendant group related to two of the species. an unrelated outgroup. O a distantly related outgroup. O a descendant related to only one of the species.arrow_forwardWhat is the most appropriate purpose of building a phylogenetic tree? They look awesome You can use a tree to compare morphological characteristics of organisms It can be used to establish and analyze evolutionary relationships between species All of the abovearrow_forward
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