Chapter 4.7, Problem 42IP

To determine

To find out how fast was the record holder running.

Answer to Problem 42IP

The record holder is running at the speed of 32.5 feet per second.

Explanation of Solution

Given information: Height of the women’s vault is about 16.5 feet.

Calculation : The speed of the runner is obtained as,

  $\begin{array}{l}\text{ h}=\frac{{\text{v}}^2}{64}\left(\text{Write the formula}\right)\\ 16.5=\frac{{\text{v}}^2}{64}\left(\text{Replace h with 16}\text{.5}\right)\\ {\text{ v}}^2=1056\\ \text{ v}=\sqrt{1056}\\ \text{ v}=32.5\left(\text{Consider the positive square root}\right)\end{array}$

Hence, the record holder is running at the speed of 32.5 feet per second.