Chapter 4.5, Problem 32IP

a.

To determine

To find : which animal is about 10 times lighter than a right whale

Answer to Problem 32IP

White rhinoceros is about 10 times lighter than a right whale

Explanation of Solution

Given information :

Thetable shows the weights of various marine and land animal.

  

Calculation :

A right whale weights $=8.82\cdot {10}^4$

An animal is 10 times lighter than a right whale

  $\begin{array}{l}=\frac{8.82\cdot {10}^4}{10}\\ =8.82\cdot {10}^{4-1}\\ =8.82\cdot {10}^3\end{array}$

White rhinoceros is about 10 times lighter than a right whalebecause white rhinoceros has $7.94\cdot {10}^3$ which is nearly $8.82\cdot {10}^3$ .

Hence, white rhinoceros is about 10 times lighter than a right whale.

b.

To determine

To find : how many time heavier is the blue whale than African elephant

Answer to Problem 32IP

The blue whale is approximately 20 times heavier them African elephant

Explanation of Solution

Given information :

The table shows the weights of various marine and land animal.

  

Calculation :

Therefore the blue whale is heavier than African elephant by

  $\begin{array}{l}=\frac{2.87\cdot {10}^5}{1.44\cdot {10}^4}\\ =\frac{2.87}{1.44}\cdot {10}^{5-4}\\ \simeq 2\cdot 10\\ \simeq 20\end{array}$

Hence, the blue whale is approximately 20 times heavier them African elephant.

c.

To determine

To write : the combined weight in scientific notation and in standard form

Answer to Problem 32IP

The combined weights is $1.9534\cdot {10}^5$ in scientific notation and the combined weights is 195340 in standard form

Explanation of Solution

Given information :

The table shows the weights of various marine and land animal.

  

Calculation :

The weight of fin whale $=9.92\cdot {10}^4$

The weight of right whale $=8.82\cdot {10}^4$

The weight of white whale $=7.94\cdot {10}^3$

The combined weight of the fin whale, right whale and white whale rhinoceros

  $\begin{array}{l}=\left(9.92\cdot {10}^4\right)+\left(8.82\cdot {10}^4\right)+\left(7.94\cdot {10}^3\right)\\ =\left(9.92+8.82\right){10}^4+\left(7.94\cdot {10}^3\right)\\ =\left(18.74\cdot {10}^4\right)+\left(7.94\cdot {10}^3\right)\\ =\left(187.4\cdot {10}^3\right)+\left(7.94\cdot {10}^3\right)\\ =\left(18.74+7.94\right)\cdot {10}^3\\ =\left(195.34\right)\cdot {10}^3\end{array}$

Hence, the combined weights is $1.9534\cdot {10}^5$ in scientific notation and the combined weights is 195340 in standard form.