Chapter 4.4, Problem 37IP

a.

To determine

To find: the value of the thickness as a decimal.

Answer to Problem 37IP

The value of thickness is $0.0000125$ centimeteras a decimal.

Explanation of Solution

Given information:

The thickness is $1.25\times {10}^{-5}$ centimeter.

Calculation:to find the thickness as a decimal move the decimal point to the left ,

  $1.25\times {10}^{-5}=0.0000125\text{ [move decimal point 5 places to the left]}$

Thus, the value of thickness is $0.0000125$ centimeter.

b.

To determine

To find: that volume of the sheet of gold.

Answer to Problem 37IP

The volume of the sheet of gold is $1.25$ cube centimeter.

Explanation of Solution

Given information:

  $\begin{array}{l}w=2m\\ l=5m\\ h=1.25\times {10}^{-5}\text{centimeter}\end{array}$

Formula used: $v=lwh$

Calculation: to find the volume, first substitute the length and width and thickness and then multiply and simplify,

  $\begin{array}{l}v=lwh\\ v=\left(500\right)\left(200\right)\left(1.25\times {10}^{-5}\right)\text{ [substitute and 1m=100centimeter]}\\ v=125000\times {10}^{-5}\text{ [multiply]}\\ v=1.25\text{ [simplify]}\end{array}$

Thus, the volume is $1.25$ cube centimeter.