Chapter 4, Problem 10CR

To determine

To evaluate: The expression $w^3+y^2$

Answer to Problem 10CR

After evaluating the expression the value is $\frac{25}{16}.$

Explanation of Solution

Given information:

The given values are; $w=-\frac{3}{4},y=1\text{ and }z=-5$

The expression can be evaluate as;

  $\begin{array}{l}{w}^3+y^2={\left(-\frac{3}{4}\right)}^2+{\left(1\right)}^2\text{ Replace w with }-\frac{3}{4}\text{ and y with 1}\\ w^3+y^2=\frac{9}{16}+1\text{ Evaluate power;}{\left(-\frac{3}{4}\right)}^2=-\frac{3}{4}\cdot -\frac{3}{4}\text{ or }\frac{9}{16}{\text{ and 1}}^2=1\cdot 1\text{ or 1}\\ w^3+y^2=\frac{25}{16}.\end{array}$ .