Chemistry & Chemical Reactivity
9th Edition
ISBN: 9781133949640
Author: John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher: Cengage Learning
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Chapter 4.7, Problem 2CYU
A 25.0-mL sample of vinegar (which contains the weak acid acetic acid, CH3CO2H) requires 28.33 mL of a 0.953 M solution of NaOH for titration to the equivalence point. What is the mass of acetic acid (molar mass = 60.05 g/mol), in grams, in the vinegar sample, and what is the concentration of acetic acid in the vinegar?
CH3CO2H(aq) + NaOH(aq) → NaCH3CO2(aq) + H2O(l)
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Consider the titration of acetic acid (CH3COOH) with sodium hydroxide to form sodium acetate (NaCH3COO) and water. A 10.0 mL sample of acetic acid requires 37.55 mL of 0.233 M NaOH to reach the equivalence point. What is the concentration of the acetic acid?
Lactic acid is a monoprotic acid with the formula C3O3H6. You have a
25.00 mL
sample of lactic acid with a concentration between
1.00 M
and
3.00 M.
To determine the exact concentration of this sample of lactic acid, you decide to perform a titration. What titrant should you use?
4. The concentration of a NaOH solution is determine by using the solution to titrate a
sample of potassium hydrogen phthalate (C8H5O4K, M = 204.22 g/mol). In the titration
34.67 mL of NaOH solution is required to react with 0.1082 g C8H5O4K to reach the
equivalence point.
a) Calculate the concentration of the sodium hydroxide solution.
Potassium hydrogen Phthalate = 0-10829, Molar mass of KMP=204-22
Hales of KMP = Mass
0.10829
g/mol
Mm
6.000529 mal
204229/Mal
Concentration of NaOH = Males
=
=
of
volume of Naot (L)
= 0-000529 mal
34-67 mе
onl ها
NaOH (mal)
= 0.000015258 mal/L
0.015M
b) This solution of sodium hydroxide is used for another titration. A sample of 10.0 mL
of HCI is neutralized using 22.1 mL of sodium hydroxide solution. Calculate the
concentration of the HCI solution.
sodium hydroxide 222.1 ml,
Nal100
Chapter 4 Solutions
Chemistry & Chemical Reactivity
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