Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN: 9780079039897
Author: Carter
Publisher: McGraw Hill
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Chapter 4.7, Problem 20PPS

a.

To determine

To find: The inverse of the function C(x) .

a.

Expert Solution
Check Mark

Answer to Problem 20PPS

  C1(x)=x5012

Explanation of Solution

Given information: The function for total monthly cost is C(x)=50+12x

Calculation:

Let the C(x) as y then rewrite the function as y=50+12x

Now, swap the variables,

  x=50+12y

Solve it for y to get inverse function.

Subtract both sides 50.

  x50=12y

Divide both sides by 12.

  x5012=12y12

Simplify it,

  y=x5012

So, the inverse function is (replace y as C1(x) )

  C1(x)=x5012

b.

To determine

To find: The quantities represented by x and C1(x) in the context of inverse function.

b.

Expert Solution
Check Mark

Answer to Problem 20PPS

In the inverse function, x represents total monthly cost and C1(x) represents number of hours spent riding.

Explanation of Solution

Given information: A function for total monthly cost C(x)=50+12x where x represents the number of hours spent on riding.

While finding the inverse of a function all x are replaced as C(x) and all C(x) as x . Thus it means the variables x and C(x) are interchanged. Then equation is solved for C(x) and C(x) is replaced as C1(x) .

c.

To determine

To find: The total number of hours spent on riding for the total cost is $338.

c.

Expert Solution
Check Mark

Answer to Problem 20PPS

Number of hours spent is 24 hours.

Explanation of Solution

Given information: In this context C(x) is $338

Calculation:

Plug in C(x) as $338 then solve it for ‘ x’

  338=50+12x

Subtract both sides 50,

  288=12x

Divide both sides by 12.

  x=24

Conclusion: Number of hours spent is 24 hours.

Chapter 4 Solutions

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

Ch. 4.1 - Prob. 5CYUCh. 4.1 - Prob. 6CYUCh. 4.1 - Prob. 7CYUCh. 4.1 - Prob. 8CYUCh. 4.1 - Prob. 9CYUCh. 4.1 - Prob. 10PPSCh. 4.1 - Prob. 11PPSCh. 4.1 - Prob. 12PPSCh. 4.1 - Prob. 13PPSCh. 4.1 - Prob. 14PPSCh. 4.1 - Prob. 15PPSCh. 4.1 - Prob. 16PPSCh. 4.1 - Prob. 17PPSCh. 4.1 - Prob. 18PPSCh. 4.1 - Prob. 19PPSCh. 4.1 - Prob. 20PPSCh. 4.1 - Prob. 21PPSCh. 4.1 - Prob. 22PPSCh. 4.1 - Prob. 23PPSCh. 4.1 - Prob. 24PPSCh. 4.1 - Prob. 25PPSCh. 4.1 - Prob. 26PPSCh. 4.1 - Prob. 27PPSCh. 4.1 - Prob. 28PPSCh. 4.1 - Prob. 29PPSCh. 4.1 - Prob. 30PPSCh. 4.1 - Prob. 31PPSCh. 4.1 - Prob. 32PPSCh. 4.1 - Prob. 33PPSCh. 4.1 - Prob. 34PPSCh. 4.1 - Prob. 35PPSCh. 4.1 - Prob. 36PPSCh. 4.1 - Prob. 37PPSCh. 4.1 - Prob. 38PPSCh. 4.1 - Prob. 39PPSCh. 4.1 - Prob. 40PPSCh. 4.1 - Prob. 41PPSCh. 4.1 - Prob. 42PPSCh. 4.1 - Prob. 43PPSCh. 4.1 - Prob. 44PPSCh. 4.1 - Prob. 45PPSCh. 4.1 - Prob. 46PPSCh. 4.1 - Prob. 47HPCh. 4.1 - Prob. 48HPCh. 4.1 - Prob. 49HPCh. 4.1 - Prob. 50HPCh. 4.1 - Prob. 51PFACh. 4.1 - Prob. 52PFACh. 4.1 - 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