Final concentration of N a C l solution if volume is doubled and number of moles is tripled has to be calculated. Concept introduction: The mass of the precipitate is depends on the reactant masses. Mole: The mole of the solute is calculated by multiplication of concentration of solution and volume of the solution and it is, Mole = Concentration (M)× volume (L) Molarity = No . of moles of solute Volume of solution in L Mass: The mass of solute present in the solution is given by multiplication of mole and molar mass of the solute. Mass = Mole × Molar mass

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Chapter 4.5, Problem 1RC

Interpretation Introduction

Interpretation:

Final concentration of NaCl solution if volume is doubled and number of moles is tripled has to be calculated.

Concept introduction:

The mass of the precipitate is depends on the reactant masses.

Mole:

The mole of the solute is calculated by multiplication of concentration of solution and volume of the solution and it is,

Mole = Concentration (M)× volume (L)

Molarity = No. of moles of soluteVolume of solution in L

Mass:

The mass of solute present in the solution is given by multiplication of mole and molar mass of the solute.

Mass = Mole × Molar mass

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