Chapter 4, Problem 4.67QP

Interpretation Introduction

Interpretation: The volume of $\text{0}\text{.416}\text{M}\text{Mg}{\left({\text{NO}}_{\text{3}}\right)}_{\text{2}}$ which has to be added to $255mL$ of $0.102MKN{O}_3$ have to be calculated using the given data.

Concept Introduction

Volumetric principle:

• In the neutralization process, the volume and concentration of initial components are equal to the volume and concentration of the final components.
• In the dilution of the chemical solutions are using this principle.
• In the dilution process, the relationship between initial and final concentrations and volumes of solutions are given in the volumetric equation and it is,

$\begin{array}{l}{\text{M}}_{\text{c}}{\text{×V}}_{\text{c}}\text{=}{\text{M}}_{\text{d}}{\text{×V}}_{\text{d}}\\ {\text{M}}_{\text{c}}\text{=}\text{Initial}\text{concentration}\\ {\text{V}}_{\text{c}}\text{=}\text{Initial}\text{volume}\\ {\text{M}}_{\text{d}}\text{=}\text{Final}\text{concentration}\\ {\text{mL}}_{\text{d}}\text{=}\text{Final}\text{volume}\end{array}$