Chapter 4, Problem 4.74QP

Interpretation Introduction

Interpretation:

The net ionic equation for the given reaction and the molar concentration of ${\text{Cu}}^{\text{+2}}$ has to be calculated.

Concept introduction:

 Net ionic equation:

 Only the species, which are contributing in participate, are written the form of ions reaction is called net ionic equation.

Spectator ions:

These are the ions that did not participate in a chemical reaction and they are found in solution before the reaction and after. They appear on the both sides of the equation and thus can be cancelled out.

Precipitation reaction:

If precipitate is formed, when two solutions mixed together is called precipitation reaction.

 Molarity:

The concentration of the solutions is given by the term of molarity and it is given by ratio between numbers of moles of solute present in litter of solution.

  $\text{Molarity}\text{=}\frac{\text{No}\text{.mole}}{\text{volume}\text{(L)}}$

 Mole:

 The mole of the solute is calculated by multiplication of concentration of solution and volume of the solution and it is,

 $\text{Mole}\text{=}\text{Concentration}\text{(M)×}\text{volume}\text{(L)}$