Chapter 4, Problem 4.92QP

(a)

Interpretation Introduction

Interpretation:

The balanced equation for the reaction of $MC{O}_3$ with $HCl$ and back titrating with remaining acid with $NaOH$ has to be written.

Concept introduction:

Balanced reaction is a chemical reaction in which number of atoms for each element in the reaction and the total charge are same on both reactant side and the product side.

Steps in balancing the information

• Step 1: Write the unbalanced equation
• Step 2: Find the coefficient to balance the equation.
• The coefficient should be reduced to the smallest whole number

(b)

Interpretation Introduction

Interpretation:

Molar mass of carbonate and element M has to be calculated.

Concept introduction:

Mole:

The mole of the solute is calculated by multiplication of concentration of solution and volume of the solution and it is,

$\text{Mole}\text{=}\text{Concentration}\text{(M)×}\text{volume}\text{(L)}$

$\text{Molarity = }\frac{\text{No}\text{. of moles of solute}}{\text{Volume of solution in L}}$

Mass:

The mass of solute present in the solution is given by multiplication of mole and molar mass of the solute.

$\text{Mass}\text{=}\text{Mole}\text{×}\text{Molar}\text{mass}$

$\text{Molar}\text{mass=}\frac{\text{Mass}}{\text{Mole of solute}}$