Explanation Approach: The method of undetermined coefficients is applicable only on nonhomogeneous equations those are polynomial, exponentials, sine or cosines or product of these function. Calculation: Consider the given equation. 2 ω ″ ( x ) − 3 ω ( x ) = 4 x sin 2 x + 4 x cos 2 x Use identity sin 2 x + cos 2 x = 1 in above equation. 2 ω ″ ( x ) − 3 ω ( x ) = <

Fundamentals of Differential Equations and Boundary Value Problems

7th Edition

ISBN: 9780321977106

Author: Nagle, R. Kent

Publisher: Pearson Education, Limited

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Chapter 4.4, Problem 6E

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Whether the method of undetermined coefficients can be applied for the particular solution of 2ω″(x)−3ω(x)=4xsin2x+4xcos2x.

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Chapter 4.4, Problem 5E

Chapter 4.4, Problem 7E

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To check: Whether the method of undetermined coefficients can be applied for the particular solution of 2 ω ″ ( x ) − 3 ω ( x ) = 4 x sin 2 x + 4 x cos 2 x .

Solution Summary: The author explains that the method of undetermined coefficients is applicable only on nonhomogeneous equations that are polynomial, exponential, sine or cosines or product of these function.

Videos

To check:

Whether the method of undetermined coefficients can be applied for the particular solution of 2ω″(x)−3ω(x)=4xsin2x+4xcos2x.

Want to see the full answer?

Chapter 4 Solutions

To check: Whether the method of undetermined coefficients can be applied for the particular solution of 2 ω ″ ( x ) − 3 ω ( x ) = 4 x sin 2 x + 4 x cos 2 x .

Solution Summary: The author explains that the method of undetermined coefficients is applicable only on nonhomogeneous equations that are polynomial, exponential, sine or cosines or product of these function.

Videos

To check: Whether the method of undetermined coefficients can be applied for the particular solution of 2ω″(x)−3ω(x)=4xsin2x+4xcos2x.

Want to see the full answer?

Chapter 4 Solutions

To check:

Whether the method of undetermined coefficients can be applied for the particular solution of 2ω″(x)−3ω(x)=4xsin2x+4xcos2x.