In Problems 15 - 22 , find the matrix product. Note that each product can be found mentally, without the use of a calculator or pencil-and-paper calculations. 1 3 5 7 3 0 0 3
In Problems 15 - 22 , find the matrix product. Note that each product can be found mentally, without the use of a calculator or pencil-and-paper calculations. 1 3 5 7 3 0 0 3
Solution Summary: The author calculates the product of the given matrices left[cc1& 3 5& 7
In Problems
15
-
22
, find the matrix product. Note that each product can be found mentally, without the use of a calculator or pencil-and-paper calculations.
Instructions.
"I have written solutions in text form, but I need experts to rewrite them in handwriting from A to Z, exactly as I have written, without any changes."
Both in images okk. Instructions.
"I have written solutions in text form, but I need experts to rewrite them in handwriting from A to Z, exactly as I have written, without any changes."
Question 1:
If a barometer were built using oil (p = 0.92 g/cm³) instead of mercury (p =
13.6 g/cm³), would the column of oil be higher than, lower than, or the same as the
column of mercury at 1.00 atm? If the level is different, by what factor? Explain. (5 pts)
Solution:
A barometer works based on the principle that the pressure exerted by the liquid column
balances atmospheric pressure. The pressure is given by:
P = pgh
Since the atmospheric pressure remains constant (P = 1.00 atm), the height of the
liquid column is inversely proportional to its density:
Step 1: Given Data
PHg
hol=hgx
Poil
• Density of mercury: PHg = 13.6 g/cm³
Density of oil: Poil = 0.92 g/cm³
• Standard height of mercury at 1.00 atm: hμg
Step 2: Compute Height of Oil
= 760 mm = 0.760 m
13.6
hoil
= 0.760 x
0.92
hoil
= 0.760 × 14.78
hoil
= 11.23 m
Step 3: Compare Heights
Since oil is less dense than mercury, the column of oil must be much taller than that of
mercury. The factor by which it is taller is:
Final…
Chapter 4 Solutions
Finite Mathematics for Business, Economics, Life Sciences and Social Sciences
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