Physics. An object dropped off the top of a tall building falls vertically with constant acceleration. If s is the distance of the object above the ground (in feet) t seconds after its release, then s and t are related by an equation of the form s = a + b t 2 where a and b are constants. Suppose the object is 180 feet above the ground 1 second after its release and 132 feet above the ground 2 seconds after its release. (A) Find the constants a and b . (B) How tall is the building? (C) How long does the object fall?
Physics. An object dropped off the top of a tall building falls vertically with constant acceleration. If s is the distance of the object above the ground (in feet) t seconds after its release, then s and t are related by an equation of the form s = a + b t 2 where a and b are constants. Suppose the object is 180 feet above the ground 1 second after its release and 132 feet above the ground 2 seconds after its release. (A) Find the constants a and b . (B) How tall is the building? (C) How long does the object fall?
Solution Summary: The author calculates the value of constants for the given distance equation, s=a+bt2, of the object when it is failing from a building.
Physics. An object dropped off the top of a tall building falls vertically with constant acceleration. If s is the distance of the object above the ground (in feet)
t
seconds after its release, then
s
and
t
are related by an equation of the form
s
=
a
+
b
t
2
where
a
and
b
are constants. Suppose the object is
180
feet above the ground 1 second after its release and
132
feet above the ground
2
seconds after its release.
Use the formulas developed in this section to find the area of the figure.
A=
(Simplify your answer.)
8.5 m
7
T
13 m
7.7 m
m
21 m
Find the circumference and area of the circle. Express answers in terms of and then round to the nearest
tenth.
Find the circumference in terms of
C =
(Type an exact answer in terms of л.)
9 cm
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