Male life expectancy. The life expectancy for males born during 1980 - 1985 was approximately 70.7 years. This grew to 71.1 years during 1985 - 1990 and to 71.8 years during 1990 - 1995 . Construct a model for this data by finding a quadratic equation whose graph passes through the points 0 , 70.7 , 5 , 71.1 and 10 , 71.8 . Use this model to estimate the life expectancy far males born between 1995 and 000 and for those born between 2000 and 2005 .
Male life expectancy. The life expectancy for males born during 1980 - 1985 was approximately 70.7 years. This grew to 71.1 years during 1985 - 1990 and to 71.8 years during 1990 - 1995 . Construct a model for this data by finding a quadratic equation whose graph passes through the points 0 , 70.7 , 5 , 71.1 and 10 , 71.8 . Use this model to estimate the life expectancy far males born between 1995 and 000 and for those born between 2000 and 2005 .
Solution Summary: The author calculates the model for the data of life expectancy for males by finding the quadratic equation that passes through the points (0,70.7).
Male life expectancy. The life expectancy for males born during
1980
-
1985
was approximately
70.7
years. This grew to
71.1
years during
1985
-
1990
and to
71.8
years during
1990
-
1995
. Construct a model for this data by finding a quadratic equation whose graph passes through the points
0
,
70.7
,
5
,
71.1
and
10
,
71.8
. Use this model to estimate the life expectancy far males born between
1995
and
000
and for those born between
2000
and
2005
.
Formula Formula A polynomial with degree 2 is called a quadratic polynomial. A quadratic equation can be simplified to the standard form: ax² + bx + c = 0 Where, a ≠ 0. A, b, c are coefficients. c is also called "constant". 'x' is the unknown quantity
Consider a sample with data values of 27, 25, 20, 15, 30, 34, 28, and 25. Compute the range, interquartile range, variance, and standard deviation (to a maximum of 2 decimals, if decimals are necessary).
Range
Interquartile range
Variance
Standard deviation
Could you explain this using the formula I attached and polar coorindates
1: Stanley Smothers receives tips from customers as a standard component of his weekly pay. He was paid $5.10/hour by his employer and received $305 in tips during the
most recent 41-hour workweek.
Gross Pay = $
2: Arnold Weiner receives tips from customers as a standard component of his weekly pay. He was paid $4.40/hour by his employer and received $188 in tips during the
most recent 47-hour workweek.
Gross Pay = $
3: Katherine Shaw receives tips from customers as a standard component of her weekly pay. She was paid $2.20/hour by her employer and received $553 in tips during the
most recent 56-hour workweek.
Gross Pay = $
4: Tracey Houseman receives tips from customers as a standard component of her weekly pay. She was paid $3.90/hour by her employer and received $472 in tips during
the most recent 45-hour workweek.
Gross Pay = $
Chapter 4 Solutions
Finite Mathematics for Business, Economics, Life Sciences and Social Sciences
Elementary Statistics: Picturing the World (7th Edition)
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