Fundamentals of Physics
10th Edition
ISBN: 9781118230718
Author: David Halliday
Publisher: Wiley, John & Sons, Incorporated
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Chapter 43, Problem 12Q
To determine
To pick:
the most likely member of each pair to be the one of the initial fragments formed by a fission event:
(a) 93Sr or 93Rb
(b) 140Gd or 140I
(c) 155Nd or 155Lu
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Pick the most likely member of each pair to be one of the initial fragments formed by a fission event: (a) 93Sr or 93Ru, (b) 140Gd or 140I, (c) 155Nd or 155Lu.
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The uranium isotope 235U can fission—break into two smaller-masscomponents and free neutrons—if it is struck by a free neutron. A typical reaction is 1/0n + 235/92U → 141/56Ba + 92/36Kr + 3/1/0nAs you can see, the subscripts (the number of protons) and the superscripts (the number of nucleons) “balance” before and after the fission event; there is no change in the number of protons or neutrons. Significant energy is released in this reaction. If a fission event happens in a large chunk of 235U, the neutrons released may induce the fission of other 235U atoms, resulting in a chain reaction. This is how a nuclear reactor works. The number of neutrons required to create a stable nucleus increases with atomic number. When the heavy 235U nucleus fissions, the lighter reaction products are thus neutron rich and are likely unstable. Many of the short-lived radioactive nuclei used in medicine are produced in fission reactions in nuclear reactors.
Because the decay…
Chapter 43 Solutions
Fundamentals of Physics
Ch. 43 - Prob. 1QCh. 43 - Prob. 2QCh. 43 - Prob. 3QCh. 43 - Prob. 4QCh. 43 - Prob. 5QCh. 43 - Prob. 6QCh. 43 - Prob. 7QCh. 43 - Which of these elements is not cooked up by...Ch. 43 - Prob. 9QCh. 43 - Prob. 10Q
Ch. 43 - Prob. 11QCh. 43 - Prob. 12QCh. 43 - Prob. 1PCh. 43 - Prob. 2PCh. 43 - Prob. 3PCh. 43 - Prob. 4PCh. 43 - Prob. 5PCh. 43 - Prob. 6PCh. 43 - Prob. 7PCh. 43 - Prob. 8PCh. 43 - Prob. 9PCh. 43 - Prob. 10PCh. 43 - Prob. 11PCh. 43 - Prob. 12PCh. 43 - Prob. 13PCh. 43 - Prob. 14PCh. 43 - Prob. 15PCh. 43 - Prob. 16PCh. 43 - Prob. 17PCh. 43 - Prob. 18PCh. 43 - Prob. 19PCh. 43 - Prob. 20PCh. 43 - Prob. 21PCh. 43 - Prob. 22PCh. 43 - Prob. 23PCh. 43 - Prob. 24PCh. 43 - SSM a A neutron of mass mn and kinetic energy K...Ch. 43 - Prob. 26PCh. 43 - Prob. 27PCh. 43 - Prob. 28PCh. 43 - Prob. 29PCh. 43 - Prob. 30PCh. 43 - Prob. 31PCh. 43 - Prob. 32PCh. 43 - Prob. 33PCh. 43 - Prob. 34PCh. 43 - Prob. 35PCh. 43 - Prob. 36PCh. 43 - Prob. 37PCh. 43 - Prob. 38PCh. 43 - Prob. 39PCh. 43 - Prob. 40PCh. 43 - Prob. 41PCh. 43 - Prob. 42PCh. 43 - Prob. 43PCh. 43 - Prob. 44PCh. 43 - Prob. 45PCh. 43 - Prob. 46PCh. 43 - SSM WWW Coal burns according to the reaction...Ch. 43 - Prob. 48PCh. 43 - Prob. 49PCh. 43 - Prob. 50PCh. 43 - Prob. 51PCh. 43 - Prob. 52PCh. 43 - Prob. 53PCh. 43 - Prob. 54PCh. 43 - Prob. 55PCh. 43 - Prob. 56PCh. 43 - Prob. 57PCh. 43 - Prob. 58P
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- (a) Calculate the energy released in the neutron- Induced fission reaction n+235U92Kr+142Ba+2n , given m(92Kr) = 91.926269 u and m(142Ba)= 141.916361 u. (b) Confirm that the total number of nucleons and total charge are conserved in this reaction.arrow_forward(a) Calculate the energy released in the neutroninduced fission reaction n+235U92Kr+142Ba+2n, given m(92Kr)=91.926269 and m(142Ba)=141.916361u. (b) Confirm that the total number at nucleons and total charge are conserved in this reaction.arrow_forward(a) Calculate the energy released in the neutron- induced fission n+238U96Sr+140Xe+3n , given m(96Sr)=95.921750uand m(140Xe)=139.92164 . This result is about 6 MeV greater than the result for spontaneous fission. Why? Confirm that the total number of nucleons and total charge are conserved in this reaction.arrow_forward
- Why can heavy nuclei with odd numbers of neutrons be induced to fission with thermal neutrons, whereas those with even numbers of neutrons require more energy input to induce fission?arrow_forwardis the heaviest stable nuclide, and its BEN is low compared with medium-mass nuclides. Calculate BEN for this nucleus and compare it with the approximate value obtained from the graph in Figure 10.7. fission of nuclei with mass numbers greater than that of Fe. are othermic processes.arrow_forwardThe uranium isotope 235U can fission—break into two smaller-masscomponents and free neutrons—if it is struck by a free neutron. A typical reaction is 1/0n + 235/92U → 141/56Ba + 92/36Kr + 3/1/0nAs you can see, the subscripts (the number of protons) and the superscripts (the number of nucleons) “balance” before and after the fission event; there is no change in the number of protons or neutrons. Significant energy is released in this reaction. If a fission event happens in a large chunk of 235U, the neutrons released may induce the fission of other 235U atoms, resulting in a chain reaction. This is how a nuclear reactor works. The number of neutrons required to create a stable nucleus increases with atomic number. When the heavy 235U nucleus fissions, the lighter reaction products are thus neutron rich and are likely unstable. Many of the short-lived radioactive nuclei used in medicine are produced in fission reactions in nuclear reactors.arrow_forward
- The uranium isotope 235U can fission—break into two smaller-masscomponents and free neutrons—if it is struck by a free neutron. A typical reaction is 1/0n + 235/92U → 141/56Ba + 92/36Kr + 3/1/0nAs you can see, the subscripts (the number of protons) and the superscripts (the number of nucleons) “balance” before and after the fission event; there is no change in the number of protons or neutrons. Significant energy is released in this reaction. If a fission event happens in a large chunk of 235U, the neutrons released may induce the fission of other 235U atoms, resulting in a chain reaction. This is how a nuclear reactor works. The number of neutrons required to create a stable nucleus increases with atomic number. When the heavy 235U nucleus fissions, the lighter reaction products are thus neutron rich and are likely unstable. Many of the short-lived radioactive nuclei used in medicine are produced in fission reactions in nuclear reactors. 235U is radioactive,…arrow_forwardThe uranium isotope 235U can fission—break into two smaller-masscomponents and free neutrons—if it is struck by a free neutron. A typical reaction is 1/0n + 235/92U → 141/56Ba + 92/36Kr + 3/1/0nAs you can see, the subscripts (the number of protons) and the superscripts (the number of nucleons) “balance” before and after the fission event; there is no change in the number of protons or neutrons. Significant energy is released in this reaction. If a fission event happens in a large chunk of 235U, the neutrons released may induce the fission of other 235U atoms, resulting in a chain reaction. This is how a nuclear reactor works. The number of neutrons required to create a stable nucleus increases with atomic number. When the heavy 235U nucleus fissions, the lighter reaction products are thus neutron rich and are likely unstable. Many of the short-lived radioactive nuclei used in medicine are produced in fission reactions in nuclear reactors. If a 238/92U nucleus…arrow_forward(a) In the case where two deuterons fuse to form a triton and a proton, what is the value of the energy released? (b) Consider a sample containing 135 cm^3 of water, where 0.015% of the molecules are D2O. Calculate the total energy released in J if all the deuteron nuclei in the sample melt according to the reaction indicated in part (a). (c) Calculate the kinetic energy released when a photon with a wavelength of 3.50x10-13 m hits a deuteron and "breaks down" it into a proton and a neutron.arrow_forward
- (a) In the case where two deuterons fuse to form a triton and a proton, what is the value of the energy released? (b) Consider a sample containing 135 cm^3 of water, where 0.015% of the molecules are D2O. Calculate the total energy released in J if all the deuteron nuclei in the sample melt according to the reaction indicated in part (a). (c) Calculate the kinetic energy released when a photon with a wavelength of 3.50x10-13 m hits a deuteron and "dismantles" it into a proton and a neutron.arrow_forwardConsider the following. n + 235U → 88Kr + 144Ba + 4 n (a) Calculate the energy (in MeV) released in the neutron-induced fission reaction above, given m(88Kr) = 87.914447 uand m(144Ba) = 143.922941 u. (Assume 1 u = 931.5 MeV/c2.) MeV (b) Confirm that the total number of nucleons and total charge are conserved in this reaction. Ai = Af= Qi = Qf=arrow_forwardConsider two 3^He and 4^He isotopes of helium (Z=2). (a) Calculate the binding energy for both elements. (b) Which one is the most cohesive (stable).(c) For both elements, draw a diagram of the energy levels occupied by the nucleons. Is it possible to understand the result of the previous item based on the level diagram? (d) Define whether the fusion reaction of 3^He + 4^He → 7^Be nuclei is energetically favorable or not.arrow_forward
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