Chapter 4.2, Problem 18PP

To determine

The smallest force needed to lift it and its resulting motion.

Explanation of Solution

Given info:

Mass of guinea pig, $m=0.50\text{ kg}$

Formula used:

Minimum force would equal to the weight of guinea pig.

$F_{lift}=F_g=mg$

Calculation:

Substituting the given values

$F_{lift}=F_g$

$=mg$

$=\left(0.50\right)\left(9.80\right)$

$=4.9\text{N}$

Conclusion:

Thus, guinea pig is lifted up from the ground the smallest force needed to lift it $4.9\text{N}$ and would move at a constant speed.