Chapter 4.3, Problem 33PP

To determine

The greatest acceleration given by the workers to bucket.

Answer to Problem 33PP

The greatest acceleration given by the workers to bucket is $0.91\text{m}/{\text{s}}^2$ .

Explanation of Solution

Given Info:

The tension in the rope is, $T=450\text{N}$

The mass of the bucket is, $m=42\text{kg}$

Formula Used:

The expression to calculate the greatest acceleration given by the workers to bucket is,

  $a=\frac{T-mg}{m}$

Calculation:

Substitute all the values in the above expression.

  $\begin{array}{c}a=\frac{450\text{N}-\left(42\text{kg}\right)\left(9.8\text{m}/{\text{s}}^2\right)}{42\text{kg}}\\ =0.91\text{m}/{\text{s}}^2\end{array}$

Thus, the greatest acceleration given by the workers to bucket is $0.91\text{m}/{\text{s}}^2$ .