Chapter 4.2, Problem 17PP

To determine

The gravitational field at the location.

Answer to Problem 17PP

  $10.45{\text{m/s}}^{\text{2}}$

Explanation of Solution

Given:

The mass of the television that is placed on a spring scale, $m=22.5\text{0 kg}$ .

Formula used:

Force due to gravity:

  $F_g=mg$

Where, m is the mass and gis the acceleration due to gravity.

Calculation:

The reading on the spring scale will be the force acting on the television due to Earth’s gravitation.

Then, using the Newton’s second law, the gravitational field at the given location is:

  $\begin{array}{c}{g}_l=\frac{F_g}{m}\\ g_l=\frac{235.2}{22.50}\\ =10.45{\text{m/s}}^{\text{2}}\end{array}$

Conclusion:

Thus, the acceleration due to gravity at the given location is $10.45{\text{m/s}}^{\text{2}}$ .