Concept explainers
Videos
(a)
Thecause of the occurrence of whiplash using Newton’s laws.
(a)
Explanation of Solution
Introduction:
Newton’s First Law of Motion: As per Newton’s First Law of Motion, an object remains in its state of rest or in motion until an external force acts on it. Whiplash is a serious neck injury of the person in the car when the car is struck from behind; the occurrence of whiplash can be explained using Newton’s Law of Motion.
Consider a person is sitting inside a car. The car seat supports the entire body of the person except for his head. When the car is suddenly struck from behind, thecar will accelerate in the forward direction.
Apply Newton’s First Law of Motion,
The seat accelerates the person’s body (except the head) in the forward direction.
As the head is not supported by the seat, it remains in its state of rest. The neck has to accelerate the head resulting in a serious neck injury.
(b)
The way headrest reduces the whiplash.
(b)
Answer to Problem 65A
The headrest reduces the whiplash as the seat accelerates the entire body of the person in the forward direction when the car is struck from behind.
Explanation of Solution
Introduction:
Newton’s First Law of Motion: As per Newton’s First Law of Motion, an object remains in its state of rest or in motion until an external force acts on it. Whiplash is a serious neck injury of the person in the car when the car is struck from behind; the occurrence of whiplash can be explained using Newton’s Law of Motion.
Consider a person is sitting inside a car. When the headrest is provided, the car seat supports the entire body of the person including the head. When the car is suddenly struck from behind, the car will accelerate in the forward direction.
Apply Newton’s First Law of Motion, the seat accelerates the person’s entire body including the head in the forward direction. Hence, this will prevent the person to suffer from a serious neck injury (whiplash).
Conclusion:
Thus, the headrest reduces the whiplash as the seat accelerates the entire body of the person in the forward direction when the car is struck from behind.
Chapter 4 Solutions
Glencoe Physics: Principles and Problems, Student Edition
Additional Science Textbook Solutions
Campbell Biology: Concepts & Connections (9th Edition)
Physics for Scientists and Engineers: A Strategic Approach, Vol. 1 (Chs 1-21) (4th Edition)
Chemistry
Anatomy & Physiology (6th Edition)
Human Physiology: An Integrated Approach (8th Edition)
Introductory Chemistry (6th Edition)
- air is pushed steadily though a forced air pipe at a steady speed of 4.0 m/s. the pipe measures 56 cm by 22 cm. how fast will air move though a narrower portion of the pipe that is also rectangular and measures 32 cm by 22 cmarrow_forwardNo chatgpt pls will upvotearrow_forward13.87 ... Interplanetary Navigation. The most efficient way to send a spacecraft from the earth to another planet is by using a Hohmann transfer orbit (Fig. P13.87). If the orbits of the departure and destination planets are circular, the Hohmann transfer orbit is an elliptical orbit whose perihelion and aphelion are tangent to the orbits of the two planets. The rockets are fired briefly at the depar- ture planet to put the spacecraft into the transfer orbit; the spacecraft then coasts until it reaches the destination planet. The rockets are then fired again to put the spacecraft into the same orbit about the sun as the destination planet. (a) For a flight from earth to Mars, in what direction must the rockets be fired at the earth and at Mars: in the direction of motion, or opposite the direction of motion? What about for a flight from Mars to the earth? (b) How long does a one- way trip from the the earth to Mars take, between the firings of the rockets? (c) To reach Mars from the…arrow_forward
- No chatgpt pls will upvotearrow_forwarda cubic foot of argon at 20 degrees celsius is isentropically compressed from 1 atm to 425 KPa. What is the new temperature and density?arrow_forwardCalculate the variance of the calculated accelerations. The free fall height was 1753 mm. The measured release and catch times were: 222.22 800.00 61.11 641.67 0.00 588.89 11.11 588.89 8.33 588.89 11.11 588.89 5.56 586.11 2.78 583.33 Give in the answer window the calculated repeated experiment variance in m/s2.arrow_forward
College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
University Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSON
Introduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Lecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-Wesley
College Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON