
Concept explainers
(a)
The reaction at
(a)

Answer to Problem 4.24P
The reaction at
Explanation of Solution
Take
Let
The free body diagram is sketched below as figure 1.
Here,
Write the expression for the moment at
Here,
Above equation implies that net moment at any point is the sum of product of each force acting on the system and perpendicular distance of the force and the point.
The moment at
Thus, the complete expression of
Here,
At equilibrium, the sum of the moment acting at
Write the expression for the net force along the
Here,
At equilibrium, the net force along the
Write the expression for the net force along the
Here,
At equilibrium, the net force along the
Let
Write the expression for the magnitude of net reaction at
Here,
Therefore, write the expression for the
Calculation:
Rearrange equation (III) to get
From figure 1, the reaction
Rearrange equation (V) to get
The
Rearrange equation (VII) to get
Substitute
Substitute
Substitute
Therefore, the reaction at
(b)
The reaction at
(b)

Answer to Problem 4.24P
The reaction at
Explanation of Solution
Take vectors along positive
Let
The free body diagram is sketched below as figure 1.
Here,
Write the expression for the moment at
Here,
Above equation implies that net moment at any point is the sum of product of each force acting on the system and perpendicular distance of the force and the point.
The moment at
Thus, the complete expression of
Here,
At equilibrium, the sum of the moment acting at
Write the expression for the net force along the
Here,
At equilibrium, the net force along the
Write the expression for the net force along the
Here,
At equilibrium, the net force along the
Let
Write the expression for the magnitude of net reaction at
Here,
Therefore, write the expression for the
Calculation:
Rearrange equation (III) to get
From figure 1, the reaction
Rearrange equation (V) to get
Substitute
The
Rearrange equation (VII) to get
Substitute
Substitute
Substitute
Therefore, the reaction at
Want to see more full solutions like this?
Chapter 4 Solutions
Vector Mechanics for Engineers: Statics and Dynamics
- MY ID#016948724 please solve the problem step by spetarrow_forward1 8 4 For the table with 4×4 rows and columns as shown Add numbers so that the sum of any row or column equals .30 Use only these numbers: .1.2.3.4.5.6.10.11.12.12.13.14.14arrow_forwardMY ID# 016948724 please solve this problem step by steparrow_forward
- The pickup truck weighs 3220 Ib and reaches a speed of 30 mi/hr from rest in a distance of 200 ft up the 10-percent incline with constant acceleration. Calculate the normal force under each pair of wheels and the friction force under the rear driving wheels. The effective coefficient of friction between the tires and the road is known to be at least 0.8.arrow_forward1. The figure shows a car jack to support 400kg (W=400kg). In the drawing, the angle (0) varies between 15 and 70 °. The links are machined from AISI 1020 hot-rolled steel bars with a minimum yield strength of 380MPa. Each link consists of two bars, one on each side of the central bearings. The bars are 300mm in length (/) and 25 mm in width (w). The pinned ends have the buckling constant (C) of 1.4 for out of plane buckling. The design factor (nd) is 2.5. (1) Find the thickness (t) of the bars and the factor of safety (n). (2) Check if the bar is an Euler beam. Darrow_forward(Read image)arrow_forward
- UNIVERSIDAD NACIONAL DE SAN ANTONIO ABAD DEL CUSCO PRIMER EXAMEN PARCIAL DE MECÁNICA DE FLUIDOS I ............ Cusco, 23 de setiembre de 2024 AP. Y NOMBRES: ........ 1.- Para el tanque de la figura: a) Calcule la profundidad de la hidrolina si la profundidad del agua es de 2.8 m y el medidor del fondo del tanque da una lectura de 52.3kPa. b) Calcule la profundidad del agua si la profundidad de la hidrolina es 6.90 m y el medidor de la parte inferior del tanque registra una lectura de 125.3 kPa. Hidrolina Sp=0.90 Abertura Agua sup suge to but amulor quit y 2.- Calcule la magnitud de la fuerza resultante sobre el área A-B y la ubicación del centro de presión. Señale la fuerza resultante sobre el área y dimensione su ubicación con claridad. 3.5 ft 12 in: Oil (38-0.93) 14 in 8 inarrow_forwardplease solve this problem and give me the correct answer step by steparrow_forwardplease solve this problem step by step and show the best way that can be explainedarrow_forward
- Elements Of ElectromagneticsMechanical EngineeringISBN:9780190698614Author:Sadiku, Matthew N. O.Publisher:Oxford University PressMechanics of Materials (10th Edition)Mechanical EngineeringISBN:9780134319650Author:Russell C. HibbelerPublisher:PEARSONThermodynamics: An Engineering ApproachMechanical EngineeringISBN:9781259822674Author:Yunus A. Cengel Dr., Michael A. BolesPublisher:McGraw-Hill Education
- Control Systems EngineeringMechanical EngineeringISBN:9781118170519Author:Norman S. NisePublisher:WILEYMechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage LearningEngineering Mechanics: StaticsMechanical EngineeringISBN:9781118807330Author:James L. Meriam, L. G. Kraige, J. N. BoltonPublisher:WILEY





