Physics for Scientists and Engineers with Modern Physics
4th Edition
ISBN: 9780131495081
Author: Douglas C. Giancoli
Publisher: Addison-Wesley
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Chapter 41, Problem 28Q
To determine
The number of
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Physics for Scientists and Engineers with Modern Physics
Ch. 41.2 - Prob. 1AECh. 41.2 - Prob. 1BECh. 41.4 - Prob. 1CECh. 41.8 - Prob. 1DECh. 41.8 - Prob. 1EECh. 41.8 - Prob. 1FECh. 41.8 - Prob. 1GECh. 41 - Prob. 1QCh. 41 - Prob. 2QCh. 41 - Prob. 3Q
Ch. 41 - Prob. 4QCh. 41 - Prob. 5QCh. 41 - How do we know there is such a thing as the strong...Ch. 41 - Prob. 7QCh. 41 - What is the experimental evidence in favor of...Ch. 41 - Prob. 9QCh. 41 - Prob. 10QCh. 41 - Prob. 11QCh. 41 - Prob. 12QCh. 41 - Prob. 13QCh. 41 - Prob. 14QCh. 41 - Prob. 15QCh. 41 - When a nucleus undergoes either or + decay, what...Ch. 41 - Prob. 17QCh. 41 - Prob. 18QCh. 41 - Prob. 19QCh. 41 - Prob. 20QCh. 41 - An isotope has a half-life of one month. After two...Ch. 41 - Prob. 22QCh. 41 - Prob. 23QCh. 41 - Prob. 24QCh. 41 - Prob. 25QCh. 41 - Prob. 26QCh. 41 - Prob. 27QCh. 41 - Prob. 28QCh. 41 - Prob. 1PCh. 41 - Prob. 2PCh. 41 - Prob. 3PCh. 41 - Prob. 4PCh. 41 - Prob. 5PCh. 41 - Prob. 6PCh. 41 - Prob. 7PCh. 41 - Prob. 8PCh. 41 - Prob. 9PCh. 41 - Prob. 10PCh. 41 - Prob. 11PCh. 41 - Prob. 12PCh. 41 - Prob. 13PCh. 41 - Prob. 14PCh. 41 - Prob. 15PCh. 41 - Prob. 16PCh. 41 - Prob. 17PCh. 41 - Prob. 18PCh. 41 - Prob. 19PCh. 41 - Prob. 20PCh. 41 - Prob. 21PCh. 41 - Prob. 22PCh. 41 - Prob. 23PCh. 41 - Prob. 24PCh. 41 - Prob. 25PCh. 41 - Prob. 26PCh. 41 - Prob. 27PCh. 41 - Prob. 28PCh. 41 - Prob. 29PCh. 41 - Prob. 30PCh. 41 - Prob. 31PCh. 41 - Prob. 32PCh. 41 - Prob. 33PCh. 41 - Prob. 34PCh. 41 - Prob. 35PCh. 41 - Prob. 36PCh. 41 - Prob. 37PCh. 41 - Prob. 38PCh. 41 - Prob. 39PCh. 41 - Prob. 40PCh. 41 - Prob. 41PCh. 41 - Prob. 42PCh. 41 - Prob. 43PCh. 41 - Prob. 44PCh. 41 - Prob. 45PCh. 41 - Prob. 46PCh. 41 - Prob. 47PCh. 41 - Prob. 48PCh. 41 - Prob. 49PCh. 41 - Prob. 50PCh. 41 - Prob. 51PCh. 41 - Prob. 52PCh. 41 - Prob. 53PCh. 41 - Prob. 54PCh. 41 - Prob. 55PCh. 41 - Prob. 56PCh. 41 - (II) The activity of a radioactive source...Ch. 41 - Prob. 58PCh. 41 - Prob. 59PCh. 41 - Prob. 60PCh. 41 - Prob. 61PCh. 41 - Prob. 62GPCh. 41 - Prob. 63GPCh. 41 - Prob. 64GPCh. 41 - Prob. 65GPCh. 41 - Prob. 66GPCh. 41 - Prob. 67GPCh. 41 - Prob. 68GPCh. 41 - Prob. 69GPCh. 41 - Prob. 70GPCh. 41 - Prob. 71GPCh. 41 - Prob. 72GPCh. 41 - Prob. 73GPCh. 41 - Prob. 74GPCh. 41 - Prob. 75GPCh. 41 - Prob. 76GPCh. 41 - Prob. 77GPCh. 41 - Prob. 78GPCh. 41 - Prob. 79GPCh. 41 - Prob. 80GPCh. 41 - (a) A 72-gram sample of natural carbon contains...Ch. 41 - Prob. 82GPCh. 41 - Prob. 83GPCh. 41 - Prob. 84GPCh. 41 - Almost all of naturally occurring uranium is...Ch. 41 - Prob. 86GPCh. 41 - Prob. 87GPCh. 41 - Prob. 88GPCh. 41 - Prob. 89GPCh. 41 - Prob. 90GP
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- Suppose you have a pure radioactive material with a half-life of T1/2. You begin with N0 undecayed nuclei of the material at t = 0. At t=12T1/2, how many of the nuclei have decayed? (a) 14N0 (b) 12N0(C) 34N0 (d) 0.707N0 (e) 0.293N0arrow_forward(a) Calculate the energy released in the a decay of 238U . (b) What fraction of the mass of a single 238U is destroyed in the decay? The mass of 234Th is 234.043593 u. (c) Although the fractional mass loss is large for a single nucleus, it is difficult to observe for an entire macroscopic sample of uranium. Why is this?arrow_forward(a) Calculate the energy released in the a decay of 238U. (b) What fraction of the mass at a single 238U is destroyed in the decay? The mass of 234Th is 234.043593 u. (c) Although the fractional mass loss is laws for a single nucleus, it is difficult to observe for an entire macroscopic sample of uranium. Why is this?arrow_forward
- The ceramic glaze on a red-orange “Fiestaware” plate is U2O3and contains 50.0 grams of 238U, but very little 235U. (a) What is the activity of the plate? (b) Calculate the total energy that will be released by the 238U decay, (c) If energy is worth 12.0 cents per kWh , what is the monetary value of the energy emitted? (These brightly- colored ceramic plates went out of production some 30 years ago, but are still available as collectibles.)arrow_forward(a) How many 239Pu nuclei must fission to produce a 20.0kT yield, assuming 200 MeV per fission? (b) What is the mass of this much 239Pu?arrow_forwardundergoes alpha decay, (a) Write the reaction equation, (b) Find the energy released in the decay.arrow_forward
- (a) Calculate the energy released in the neutron- Induced fission reaction n+235U92Kr+142Ba+2n , given m(92Kr) = 91.926269 u and m(142Ba)= 141.916361 u. (b) Confirm that the total number of nucleons and total charge are conserved in this reaction.arrow_forwardDerive an approximate relationship between the energy of (decay and halflife using the following data. It may be useful to graph the leg t1/2 against Ea to find some straightline relationship. Table 31.3 Energy and HalfLife for (Decay Nuclide E( (MeV) t1/2 216Ra 9.5 0.18 (s 194Po 7.0 0.7 s 240Cm 6.4 27 d 226Ra 4.91 1600 y 232Th 4.1 1.41010yarrow_forward(a) Calculate the radius of 58Ni, one of the most tightly bound stable nuclei. (b) What is the ratio of the radius of 58Ni to that at 258Ha, one of the largest nuclei ever made? Note that the radius of the largest nucleus is still much smaller than ?le size of an atom.arrow_forward
- (a) A cancer patient is exposed to rays from a 5000Ci 60Co transillumination unit for 32.0 s. The rays are collimated in such a manner that only 1.00% of them strike the patient. Of those, 20.0% are absorbed in a tumor having a mass of 1.50 kg. What is the dose in rem to the tumor, it the average energy per decay is 1.25 MeV? None of the s from the decay reach the patient. (b) Is the dose consistent with stated therapeutic doses?arrow_forward(a) Write the decay equation for the decay of 235U. (b) What energy is released in this decay? The mass of the daughter nuclide is 231.036298 u. (c) Assuming the residual nucleus is formed in its ground state, how much energy goes to the particle?arrow_forward(a) Neutron activation of sodium, which is 100% 23Na, produces 24Na, which is used in some heart scans, as seen in Table 32.1. The equation for the reaction is 23Na+n24Na+ . Find its energy output, given the mass of 24Na is 23.990962 u. (b) What mass at 24Na produces the needed 5.0mCi activity, given its halflife is 15.0 h?arrow_forward
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