Explanation Given Information: The provided matrices are A = [ 1 − 1 0 0 2 − 1 ] , B = [ 3 0 − 1 5 − 1 1 ] and C = [ x 1 w z r 4 ] . Formula used: A matrix with m rows and n columns is of dimension m × n , where, m and n are positive integers. For two matrices A and B with equal dimensions, A + B and A − B is the sum and difference of the corresponding entries of the matrices respectively as, ( A + B ) i j = A i j + B i j ( A − B ) i j = A i j − B i j Calculation: Consider the matrices, A = [ 1 − 1 0 0 2 − 1 ] , B = [ 3 0 − 1 5 − 1 1 ] and C = [ x 1 w z r 4 ] Recall that, a matrix with m rows and n columns is of dimension m × n , where, m and n are positive integers. Here, number of rows in A = [ 1 − 1 0 0 2 − 1 ] is 2 and number of columns is 3 . Substitute 2 for m and 3 for n in m × n , Thus, dimension of A = [ 1 − 1 0 0 2 − 1 ] is 2 × 3 . Now, number of rows in B = [ 3 0 − 1 5 − 1 1 ] is 2 and number of columns is 3

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Author: Stefan Waner, Steven Costenoble

Publisher: Cengage Learning

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Chapter 4.1, Problem 23E

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To calculate: The value of A−B+C, where, A=[1−1 00 2−1], B=[3 0−15−1 1] and C=[x1wzr4].

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Chapter 4.1, Problem 22E

Chapter 4.1, Problem 24E

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The value of A − B + C , where, A = [ 1 − 1 0 0 2 − 1 ] , B = [ 3 0 − 1 5 − 1 1 ] and C = [ x 1 w z r 4 ] .

Solution Summary: The author calculates the value of A-B+C and B=left[cc1& 0 0&

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To calculate: The value of A−B+C, where, A=[1−1 00 2−1], B=[3 0−15−1 1] and C=[x1wzr4].

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Chapter 4 Solutions