DeGarmo's Materials and Processes in Manufacturing
12th Edition
ISBN: 9781118987674
Author: J. T. Black, Ronald A. Kohser
Publisher: WILEY
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Chapter 40, Problem 6P
To determine
To determine the lot size to justify the use of jig.
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ASSIGNMENT-2
Tool Box
Objective: To perform cutting and forming processes on a sheet metal to produce a tool box
with SIZE of 445mmL x 281mmW x 220mmH, with handle holes diameter 20mm.
Note : assume any missing dimensions
a) List the tools used
b) Write the steps to preapare
c) Sketch each steps
Solve it
A NC lathe cuts two passes across a cylindrical workpiece under automatic cycle. The operator loads and unloads the machine. The starting diameter of the work is 3.00 in and its length = 10 in. The work cycle consists of the following steps (with element times given in parentheses where applicable):
1 - Operator loads part into machine, starts cycle (1.00 min);
2 - NC lathe positions tool for first pass (0.10 min);
3 - NC lathe turns first pass (time depends on cutting speed);
4 - NC lathe repositions tool for second pass (0.4 min);
5 - NC lathe turns second pass (time depends on cutting speed); and
6 - Operator unloads part and places in tote pan (1.00 min).
In addition, the cutting tool must be periodically changed. This tool change time takes 1.00 min. The feed rate = 0.007 in/rev and the depth of cut for each pass = 0.100 in. The cost of the operator and machine = $39/hr and the tool cost = $2.00/cutting edge. The applicable Taylor tool life equation has parameters: n = 0.26 and…
Chapter 40 Solutions
DeGarmo's Materials and Processes in Manufacturing
Ch. 40 - What are the two primary functions of a...Ch. 40 - Prob. 2RQCh. 40 - An early treatise defined a jig as a device that...Ch. 40 - Does an ordinary vise qualify as a fixture? Why or...Ch. 40 - What basic criteria should be considered in...Ch. 40 - In any part drawing, what are the critical...Ch. 40 - What difficulties can result from not keeping...Ch. 40 - Prob. 8RQCh. 40 - Which of the basic design principles relating to...Ch. 40 - What are the two reasons for not having drill...
Ch. 40 - Why does the use of down milling often make it...Ch. 40 - Prob. 12RQCh. 40 - A large assembly jig for an airplane-wing...Ch. 40 - Explain why the use of a given fixture may not be...Ch. 40 - Prob. 15RQCh. 40 - In the clamps shown in Figure 40.20, what is the...Ch. 40 - What are other common types of clamp?Ch. 40 - What is the purpose of dimensioning the...Ch. 40 - Prob. 19RQCh. 40 - In Figure 49.9. why arent there three points put...Ch. 40 - Which set of locators in Figure 49.9 establishes...Ch. 40 - What are the four stages of the SMED methodology...Ch. 40 - Prob. 23RQCh. 40 - How could the intermediate jig concept be used in...Ch. 40 - Develop a sequence of operations to produce the...Ch. 40 - Suppose in the sample problem at the end of this...Ch. 40 - Notice that the holes in the part in Figure 49.9...Ch. 40 - Prob. 6PCh. 40 - A part has two holes located for drilling by...
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- Expert Q&A Done The top surface of a rectangular workpart is machined using a peripheral milling operation. The workpart is 735 mm long by 50 mm wide by 95 mm thick. The milling cutter, which is 60 mm in diameter and has five teeth, overhangs the width of the part equally on both sides. Cutting speed = 80 m/min, chip load = 0.30 mm/tooth, and depth of cut = 7.5 mm. (a) Determine the time required to make one pass across the surface, given that the setup and machine settings provide an approach distance of 5 mm before actual cutting begins and an overtravel distance of 25 mm after 1.2 9. 20 65 73 actual cutting has finished v in seconds. (b) What is the maximum material 3.9 239 removal rate during the cut v in mm3/sec? 0.127 5arrow_forwardILLUSTRATION 2: An operator manufactures 50 jobs in 6 hours and 30 minutes. If this time includes the time for setting his machine. Standard time allowed for the job was: Setting time = 35 min Production time per piece = 8 min %3Darrow_forwardA step by step answer pleasearrow_forward
- An articulated robot loads and unloads a CNC machine tool. The cell is scheduled to produce abatch of 300 parts. Setting up the cell for this part style takes 30 min, programming the robot takes75 min, and programming the CNC machine tool takes 55 min. For safety reasons, these threesetup activities must be done sequentially. The programmed machining cycle takes 3.75 min.Cutting tools wear out and must be periodically changed, which takes 6.0 min every 20 cycles andis performed by a human worker. At the end of each machining cycle, the robot reaches into themachine and removes the just-completed part, places it in a parts storage carousel, then reachesfor a starting work part from the same carousel and places it in the machine tool fixture. Thissequence of handling activities takes 45 sec. The storage carousel holds 25 parts. At the beginningof the production run, it is full of raw work parts. As each part is retrieved by the robot, the carouselindexes one position to present a new raw…arrow_forwardoperation, the shear IS cIose to, In turning operation, spindle speed is set to provide a cutting speed of 2.2 m/: The feed and depth of cut are 0.32 mm and 2.1 mm, respectively. The tool rake angle is 15°. After the cut, the deformed chip thickness is measured to be 0.43 mm. Using the Orthogonal model as an approximation of turning operation, the shear strain is close to, In turning operation, spindle speed is set to provide a cutting speed of 2.4 m/arrow_forwardCheck the picturearrow_forward
- The Conner Company uses a two-step process for making wooden boards with holes in them. Step 1 is drilling and Step 2 is sanding. Drilling is done using an electronic drill that takes 8 minutes to set up and ½ minute to drill each hole. Step 2 involves a sanding machine with a 20 minute setup time that processes each board (regardless of how many holes are in it) in 10 minutes. If all orders are for a single batch of 10 boards, and each board has 14 holes what is the capacity of this 2-step process? (Assume that both machines only need to be set up once.)arrow_forwardAn order for 100 of a product is processed on work centers A and B. The setup time on A is 30 minutes, and run time is 10 minutes per piece. The setup time on B is 50 minutes, and the run time is 5 minutes per piece. Wait time between the two operations is 4 hours. The move time between A and B is 10 minutes. Wait time after operation B is 4 hours, and the move time into stores is 15 minutes. There is no queue at either workstation. If it is decided to overlap operations A and B by splitting the lot of 100 into two lots of 70 and 30. Wait time between A and B and between B and stores is eliminated. Setup on operation B can start before the first batch arrives. Calculate the manufacturing lead time for the whole order. Calculate the manufacturing lead time for the first patch.arrow_forwardTask 4 Here students need to calculate (a) The cutting speed (b) Turning time (c) Amount of material removed. For a specimen as shown below, if spindle rotates at N = 360 rpm, number of pass = 03, feed rate= 0.2mm/rev, if density of material=7.85× 10-6 Kg/mm³. Appendix Volume for Cylinder = rr?h Volume of frustum= nh (a?+b²+ab)/3 radii 'a' & b' height(Length) 'h'. b-a Taper angle : = tan20 h TDN Cutting speed:V : meters/min 1000 Where: V = Cutting speed in Meter/minute. T= 3.14 D = Diameter of work piece in mm N = rpm Cutting Time Length of the job to be turned NO.of cuts Time to turn mins. Feed/Rev rpm Amount of Material Removed = Original Mass – Machined Mass Original Size of Component 380 mm Machined Component 80 mm 100 mm 120 mm 6 20mm + 25mm + 40mm + 25mm 030mmarrow_forward
- A production process at Kenneth Day Manufacturing is shown in the figure below. The drilling operation occurs separately from, and simultaneously with, the sawing and sanding, which are independent sequential operations. A product needs to go through only one of the three assembly operations (the operations are in parallel). 2.1 units/hr Sawing 7 units/hr Sanding Drilling 6 units/hr Welding 2.5 units/hr a) Sawing is the bottleneck. b) The bottleneck time is 28.57 minutes per unit (round your response to two decimal places). c) The throughput time of the overall system is minutes (round your response to two decimal places). Assembly 0.8 units/hr Assembly 0.8 units/hr Assembly 0.8 units/hrarrow_forward3)arrow_forwardWrite TRUE is the statement/s is True. If the statement is false, identify the word/s that makes the sentence incorrect and write its corresponding correct answer. 7. In planning, the tool travels along the workpiece during the removal of the material on the workpiece. 8. The factors that can be manipulated in cutting process are cutting speed, feed and depth of cut. 9.In thermally assisted machining, the tool is heated which reduces the required cutting force.arrow_forward
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