DeGarmo's Materials and Processes in Manufacturing
12th Edition
ISBN: 9781118987674
Author: J. T. Black, Ronald A. Kohser
Publisher: WILEY
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Textbook Question
Chapter 40, Problem 4RQ
Does an ordinary vise qualify as a fixture? Why or why not?
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Example-1:
l
D
A uniform rotor of length 0.6 m and diameter 0.4 m is made of steel (density 7810 kg/m³)
is supported by identical short bearings of stiffness 1 MN/m in the horizontal and vertical
directions. If the distance between the bearings is 0.7 m, determine the natural frequencies
and plot whirl speed map.
Solution:
B
find the laplace transform for the
flowing function
2(1-e)
Ans. F(s)=-
S
12)
k
0
Ans. F(s)=
k
s(1+e)
0 a
2a 3a 4a
13)
2+
Ans. F(s)=
1
s(1+e")
3
14) f(t)=1, 0
Find the solution of the following Differential Equations
Using Laplace Transforms
1) 4y+2y=0.
y(0)=2.
y'(0)=0.
2) y+w²y=0,
(0)=A,
y'(0)=B.
3) +2y-8y 0.
y(0)=1.
y'(0)-8.
4)-2-3y=0,
y(0)=1.
y'(0)=7.
5) y-ky'=0,
y(0)=2,
y'(0)=k.
6) y+ky'-2k²y=0,
y(0)=2,
y'(0) = 2k.
7) '+4y=0,
y(0)=2.8
8) y+y=17 sin(21),
y(0)=-1.
9) y-y-6y=0,
y(0)=6,
y'(0)=13.
10) y=0.
y(0)=4,
y' (0)=0.
11) -4y+4y-0,
y(0)=2.1.
y'(0)=3.9
12) y+2y'+2y=0,
y(0)=1,
y'(0)=-3.
13) +7y+12y=21e".
y(0)=3.5.
y'(0)=-10.
14) "+9y=10e".
y(0)=0,
y'(0)=0.
15) +3y+2.25y=91' +64.
y(0)=1.
y'(0) = 31.5
16)
-6y+5y-29 cos(2t).
y(0)=3.2,
y'(0)=6.2
17) y+2y+2y=0,
y(0)=0.
y'(0)=1.
18) y+2y+17y=0,
y(0)=0.
y'(0)=12.
19) y"-4y+5y=0,
y(0)=1,
y'(0)=2.
20) 9y-6y+y=0,
(0)-3,
y'(0)=1.
21) -2y+10y=0,
y(0)=3,
y'(0)=3.
22) 4y-4y+37y=0,
y(0)=3.
y'(0)=1.5
23) 4y-8y+5y=0,
y(0)=0,
y'(0)=1.
24)
++1.25y-0,
y(0)=1,
y'(0)=-0.5
25) y 2 cos(r).
y(0)=2.
y'(0) = 0.
26)
-4y+3y-0,
y(0)=3,
y(0) 7.
27) y+2y+y=e
y(0)=0.
y'(0)=0.
28) y+2y-3y=10sinh(27),
y(0)=0.
y'(0)=4.
29)…
Chapter 40 Solutions
DeGarmo's Materials and Processes in Manufacturing
Ch. 40 - What are the two primary functions of a...Ch. 40 - Prob. 2RQCh. 40 - An early treatise defined a jig as a device that...Ch. 40 - Does an ordinary vise qualify as a fixture? Why or...Ch. 40 - What basic criteria should be considered in...Ch. 40 - In any part drawing, what are the critical...Ch. 40 - What difficulties can result from not keeping...Ch. 40 - Prob. 8RQCh. 40 - Which of the basic design principles relating to...Ch. 40 - What are the two reasons for not having drill...
Ch. 40 - Why does the use of down milling often make it...Ch. 40 - Prob. 12RQCh. 40 - A large assembly jig for an airplane-wing...Ch. 40 - Explain why the use of a given fixture may not be...Ch. 40 - Prob. 15RQCh. 40 - In the clamps shown in Figure 40.20, what is the...Ch. 40 - What are other common types of clamp?Ch. 40 - What is the purpose of dimensioning the...Ch. 40 - Prob. 19RQCh. 40 - In Figure 49.9. why arent there three points put...Ch. 40 - Which set of locators in Figure 49.9 establishes...Ch. 40 - What are the four stages of the SMED methodology...Ch. 40 - Prob. 23RQCh. 40 - How could the intermediate jig concept be used in...Ch. 40 - Develop a sequence of operations to produce the...Ch. 40 - Suppose in the sample problem at the end of this...Ch. 40 - Notice that the holes in the part in Figure 49.9...Ch. 40 - Prob. 6PCh. 40 - A part has two holes located for drilling by...
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