Chapter 4, Problem 9MCP

Interpretation Introduction

Interpretation:

Among the given compounds, the one which has fewer moles of carbon has to be given.

  $\begin{array}{l}\text{6}\text{.02}\times {\text{10}}^{22}{\text{ molecules of C}}_{\text{2}}{\text{H}}_{\text{6}}\\ {\text{88 g of CO}}_2\end{array}$

Concept Introduction:

Moles:

Mole of the substance is found by dividing the mass of the substance by its molar mass.

  $\text{No}\text{. of moles (n) = }\frac{\text{mass}}{\text{Molar mass}}$