Chapter 4, Problem 89P

Interpretation Introduction

(a)

Interpretation:

The combustion equation for palmitic acid and glucose is given as.

$\begin{array}{l}{\text{C}}_{\text{16}}{\text{H}}_{\text{32}}{\text{O}}_{\text{2}}{\text{ (aq) + O}}_{\text{2}}\text{(g) }\stackrel{}{\to }{\text{CO}}_{\text{2}}{\text{(g) + H}}_{\text{2}}\text{O(l) + 2385 kcal /mol}\\ \text{Palmitic acid}\\ \text{(256 g/mol)}\end{array}$

$\begin{array}{l}{\text{C}}_{\text{6}}{\text{H}}_{\text{12}}{\text{O}}_{\text{6}}{\text{ (aq) + O}}_{\text{2}}\text{(g) }\stackrel{}{\to }{\text{CO}}_{\text{2}}{\text{(g) + H}}_{\text{2}}\text{O(l) + 670 kcal /mol}\\ \text{Glucose}\\ \text{(180 g/mol)}\end{array}$

Balance the reactions.

Concept Introduction:

The balanced reaction will be obtained by reaction of organic compound with oxygen where carbon is converted to carbon dioxide and hydrogen is converted to water.

Each atom of carbon will be converted to one molecule of carbon dioxide and two atoms of hydrogen will give one molecule of water.

Interpretation Introduction

(b)

Interpretation:

What will be the heat of combustion of plamitic acid and glucose in kcal /g? The unbalanced chemical equations are.

$\begin{array}{l}{\text{C}}_{\text{16}}{\text{H}}_{\text{32}}{\text{O}}_{\text{2}}{\text{ (aq) + O}}_{\text{2}}\text{(g) }\stackrel{}{\to }{\text{CO}}_{\text{2}}{\text{(g) + H}}_{\text{2}}\text{O(l) + 2385 kcal /mol}\\ \text{Palmitic acid}\\ \text{(256 g/mol)}\end{array}$

$\begin{array}{l}{\text{C}}_{\text{6}}{\text{H}}_{\text{12}}{\text{O}}_{\text{6}}{\text{ (aq) + O}}_{\text{2}}\text{(g) }\stackrel{}{\to }{\text{CO}}_{\text{2}}{\text{(g) + H}}_{\text{2}}\text{O(l) + 670 kcal /mol}\\ \text{Glucose}\\ \text{(180 g/mol)}\end{array}$

Concept Introduction:

The heat produced by one gram of a fuel is calculated as.

$\text{Heat /g = }\frac{\text{Heat produced from one mole}}{\text{Molar mass}}$.

Interpretation Introduction

(c)

Interpretation:

The combustion equation for palmitic acid and glucose is given as.

$\begin{array}{l}{\text{C}}_{\text{16}}{\text{H}}_{\text{32}}{\text{O}}_{\text{2}}{\text{ (aq) + O}}_{\text{2}}\text{(g) }\stackrel{}{\to }{\text{CO}}_{\text{2}}{\text{(g) + H}}_{\text{2}}\text{O(l) + 2385 kcal /mol}\\ \text{Palmitic acid}\\ \text{(256 g/mol)}\end{array}$

$\begin{array}{l}{\text{C}}_{\text{6}}{\text{H}}_{\text{12}}{\text{O}}_{\text{6}}{\text{ (aq) + O}}_{\text{2}}\text{(g) }\stackrel{}{\to }{\text{CO}}_{\text{2}}{\text{(g) + H}}_{\text{2}}\text{O(l) + 670 kcal /mol}\\ \text{Glucose}\\ \text{(180 g/mol)}\end{array}$

Based on reaction and heat produced which is better fuel (source of energy) in terms of kcal /mol?

Concept Introduction:

The fuel which will produce more amount per mole will be considered as better fuel (source of energy).

Interpretation Introduction

(d)

Interpretation:

The combustion equation for palmitic acid and glucose is given as.

$\begin{array}{l}{\text{C}}_{\text{16}}{\text{H}}_{\text{32}}{\text{O}}_{\text{2}}{\text{ (aq) + O}}_{\text{2}}\text{(g) }\stackrel{}{\to }{\text{CO}}_{\text{2}}{\text{(g) + H}}_{\text{2}}\text{O(l) + 2385 kcal /mol}\\ \text{Palmitic acid}\\ \text{(256 g/mol)}\end{array}$

$\begin{array}{l}{\text{C}}_{\text{6}}{\text{H}}_{\text{12}}{\text{O}}_{\text{6}}{\text{ (aq) + O}}_{\text{2}}\text{(g) }\stackrel{}{\to }{\text{CO}}_{\text{2}}{\text{(g) + H}}_{\text{2}}\text{O(l) + 670 kcal /mol}\\ \text{Glucose}\\ \text{(180 g/mol)}\end{array}$

Based on reaction and heat produced which is better fuel (source of energy) in terms of kcal /g?

Concept Introduction:

The fuel which will produce more amount per gram will be considered as better fuel (source of energy).