Concept explainers
(a)
Interpretation:
Lone pairs should be added where needed and the total number of valence electrons in glycine should be counted.
Concept Introduction:
Valence electrons are the electrons reside in valence shell of an atom and valence electrons are the ones which participate in bonding. In main group elements, group number equals to the number of valence electrons. The sum gives the total number of valence electrons in a molecule.
(b)
Interpretation:
The shape around the four indicated atoms should be determined.
Concept Introduction:
To determine the shape around a given
(c)
Interpretation:
All polar bonds in glycine should be labeled.
Concept Introduction:
The electronegativity difference can be used to differentiate bonds as polar, polar covalent and ionic bonds in different compounds.
If the electronegativity difference between two atoms is less than 0.5, the bond is nonpolar in which electrons are equally shared. If the electronegativity difference is between 0.5 − 1.9, the bond is polar covalent, in which electrons are unequally shared, the electron density is more towards electronegative atom. For electronegativity difference more than 1.9, the bond is ionic, in which electrons has been transferred from the less electronegative atom to more electronegative atom.
(e)
Interpretation:
Whether the glycine is a polar molecule should be determined.
Concept Introduction:
Polarity of a molecule depends on the individual bonds and the overall shape. If a molecule has no polar bonds, then the molecule is nonpolar. If the molecule has one polar bond, then the molecule is considered to be polar. If a molecule has more than one polar bond, the shape of the molecule determines the polarity of the molecule. If the bond dipoles do not cancel, the molecule is polar. If they get cancelled, the molecule is non-polar.
Want to see the full answer?
Check out a sample textbook solutionChapter 4 Solutions
GENERAL,ORGANIC, & BIOLOGICAL CHEM-ACCES
- Part V. Choose which isomer would give the 1H-NMR spectrum below. Justify your reasoning by assigning important signals to the Corresponding protons of the correct molecule. A D on of of of H H 88 2 90 7.8 7.6 7.4 80 5 6 [ppm] 7.2 6.8 6.6 6.4 ō [ppm]arrow_forwardShow work with explanation. don't give Ai generated solutionarrow_forwardQ7. a. Draw the line-bond structure of the major product for the following reaction, if a reaction occurs, assume monohalogenation. b. Calculate the product ratios using the following information (hint: use the number of hydrogens in each category present to calculate the ratios). Chlorination: 1° Reactivity=1 2° Reactivity=4 Heat + Cl2 3° Reactivity=5arrow_forward
- Please correct answer and don't use hand rating and don't use Ai solutionarrow_forwardQ10: Alkane halogenation a. Give the name and structures of the five isomeric hexanes. Page 4 of 5 Chem 0310 Organic Chemistry 1 Recitations b. For each isomer, give all the free radical monochlorination and monobromination products that are structurally isomeric.arrow_forwardQ9. The insecticide DDT (in the box below) is useful in controlling mosquito populations and has low toxicity to humans, but is dangerous to birds and fish. Hoping to alleviate the dangers, little Johnny Whizbang, an aspiring chemist, proposes a new version of DDT ("Bromo-DDT") and shows his synthesis to his boss. Will Johnny Whizbang's synthesis work? Or will he be fired? Assume there is an excess of bromine and polybrominated products can be separated. Explain why. CH3 Br2, light CBR3 ok-ok Br Br Br Br CI "Bromo-DDT" CCl 3 DDT (dichlorodiphenyltrichloroethane) CIarrow_forward
- Differentiate the terms Monotectic, Eutectic, Eutectoid, Peritectic, Peritectoid.arrow_forwardQ5. Predict the organic product(s) for the following transformations. If no reaction will take place (or the reaction is not synthetically useful), write "N.R.". Determine what type of transition state is present for each reaction (think Hammond Postulate). I Br₂ CH3 F2, light CH3 Heat CH3 F₂ Heat Br2, light 12, light CH3 Cl2, lightarrow_forwarda. For the following indicated bonds, rank them in order of decreasing AH° for homolytic cleavage. Based on your answer, which bond would be most likely to break homolytically? (a) (c) H3C CH3 .CH3 CH3 CH3 (b) Page 1 of 5 Chem 0310 Organic Chemistry 1 Recitations b. Draw all the possible radical products for 2-methylbutane, and determine which bond is most likely to be broken.arrow_forward
- A 5-m³ rigid tank contains 5 kg of water at 100°C. Determine (a) the pressure, (b) the total enthalpy, and (c) the mass of each phase of water.arrow_forwardQ8. Draw the mechanism for this halogenation reaction. Show all steps including initiation, propagation, and recombination. Cl₂, hv CI Br Br2, hv, heatarrow_forwardQ6. Given the following alkanes, draw the most likely product to form upon monohalogenation with Br2 (keep in mind that this may not be the only product to form though). If the reaction was performed with Cl2 would there be more or less selectivity in the desired product formation? Why? (a) (b) (c)arrow_forward
- Chemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub CoWorld of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage LearningLiving By Chemistry: First Edition TextbookChemistryISBN:9781559539418Author:Angelica StacyPublisher:MAC HIGHER
- Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage LearningOrganic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning