Computer Science Illuminated
6th Edition
ISBN: 9781284055917
Author: Nell Dale, John Lewis
Publisher: Jones & Bartlett Learning
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Chapter 4, Problem 68E
Explanation of Solution
a.
Combinational circuit with memory elements:
- A circuit used in memory is the sequential circuit. Because, the present state output of the circuit as the input of the circuit to determine the next state output.
- The output of sequential circuit is determined by its present input values and also by its past output of the sequential circuit.
- One type of the memory circuit is S-R latch...
Explanation of Solution
b.
Number of digits is stored in S-R latch:
- S-R latch:
- S-R latch is a type of memory circuit.
- It is a sequential circuit because the present state output of the circuit as the input of the circuit to determine the next state output.
- An S-R latch can store the single binary digit values (0 or 1).
- Block diagram for the S-R latch is shown below:
Explanation of Solution
c.
Output of the S-R latch:
- S-R latch:
- S-R latch is a type of memory circuit.
- It is a sequential circuit because the present state output of the circuit as the input of the circuit to determine the next state output.
- An S-R latch can store the single binary digit values (0 or 1).
- The design of the S-R latch circuit produces two outputs, X and Y.
- The outputs of the S-R latch always complement each other.
- When the output X is 0, then Y is 1. Likewise, when the output X is 1, then Y is 0.
- Block diagram for the S-R latch is shown below:
- From the S-R latch diagram:
- S and R are the input for the first and second NAND gate, respectively.
- The output X is another input for the second NAND gate, and the output Y is another input for the first NAND gate...
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Please provide the Mathematica code
Chapter 4 Solutions
Computer Science Illuminated
Ch. 4 - Prob. 1ECh. 4 - Prob. 2ECh. 4 - Prob. 3ECh. 4 - Prob. 4ECh. 4 - Prob. 5ECh. 4 - Prob. 6ECh. 4 - Prob. 7ECh. 4 - Prob. 8ECh. 4 - Prob. 9ECh. 4 - Prob. 10E
Ch. 4 - Prob. 11ECh. 4 - Prob. 12ECh. 4 - Prob. 13ECh. 4 - Prob. 14ECh. 4 - Prob. 15ECh. 4 - Prob. 16ECh. 4 - Prob. 17ECh. 4 - Prob. 18ECh. 4 - Prob. 19ECh. 4 - Prob. 20ECh. 4 - Prob. 21ECh. 4 - Prob. 22ECh. 4 - Prob. 23ECh. 4 - Prob. 24ECh. 4 - Prob. 25ECh. 4 - Prob. 26ECh. 4 - Prob. 27ECh. 4 - Prob. 28ECh. 4 - Prob. 29ECh. 4 - Prob. 30ECh. 4 - Prob. 31ECh. 4 - Prob. 32ECh. 4 - Prob. 33ECh. 4 - Prob. 34ECh. 4 - Prob. 35ECh. 4 - Prob. 36ECh. 4 - Prob. 37ECh. 4 - Prob. 38ECh. 4 - Prob. 39ECh. 4 - Prob. 40ECh. 4 - Prob. 41ECh. 4 - Prob. 42ECh. 4 - Prob. 43ECh. 4 - Prob. 44ECh. 4 - Prob. 45ECh. 4 - Prob. 46ECh. 4 - Prob. 47ECh. 4 - Prob. 48ECh. 4 - Prob. 49ECh. 4 - Prob. 50ECh. 4 - Prob. 51ECh. 4 - Prob. 52ECh. 4 - Prob. 53ECh. 4 - Prob. 54ECh. 4 - Prob. 55ECh. 4 - Prob. 56ECh. 4 - Prob. 57ECh. 4 - Prob. 58ECh. 4 - Prob. 59ECh. 4 - Prob. 60ECh. 4 - Prob. 61ECh. 4 - Prob. 62ECh. 4 - Prob. 63ECh. 4 - Prob. 64ECh. 4 - Prob. 65ECh. 4 - Prob. 66ECh. 4 - Prob. 67ECh. 4 - Prob. 68ECh. 4 - Prob. 69ECh. 4 - Prob. 70ECh. 4 - Prob. 71ECh. 4 - Prob. 72ECh. 4 - Prob. 73ECh. 4 - Prob. 1TQCh. 4 - Prob. 2TQCh. 4 - Prob. 3TQCh. 4 - Prob. 4TQ
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