The increase in bond strength by the removal of an electron in case of O 2 and the decrease in bond strength by the removal of an electron from N 2 is to be explained. Concept introduction: The electronic configuration for multi-electron diatomic is written using the molecular orbitals, derived from the H 2 + molecular ion. The bond order is calculated by difference between the anti-bonding electrons and the bonding electrons by two. This can be stated as, Bond order = [ ( Electrons in bonding orbitals ) − ( Electrons in anti-bonding orbitals ) ] 2 As the bond order increases, the stability also increases. The bond order is directly proportional to the bond energy and inversely proportional to the bond length. To determine: The reason behind the increase in bond strength in case of O 2 and the decrease in the same in case of N 2 on the removal of an electron.
The increase in bond strength by the removal of an electron in case of O 2 and the decrease in bond strength by the removal of an electron from N 2 is to be explained. Concept introduction: The electronic configuration for multi-electron diatomic is written using the molecular orbitals, derived from the H 2 + molecular ion. The bond order is calculated by difference between the anti-bonding electrons and the bonding electrons by two. This can be stated as, Bond order = [ ( Electrons in bonding orbitals ) − ( Electrons in anti-bonding orbitals ) ] 2 As the bond order increases, the stability also increases. The bond order is directly proportional to the bond energy and inversely proportional to the bond length. To determine: The reason behind the increase in bond strength in case of O 2 and the decrease in the same in case of N 2 on the removal of an electron.
Solution Summary: The author explains that the increase in the bond order on the removal of an electron is the reason behind the stability of the O_ 2 molecule.
Interpretation: The increase in bond strength by the removal of an electron in case of
O2 and the decrease in bond strength by the removal of an electron from
N2 is to be explained.
Concept introduction: The electronic configuration for multi-electron diatomic is written using the molecular orbitals, derived from the
H2+ molecular ion.
The bond order is calculated by difference between the anti-bonding electrons and the bonding electrons by two. This can be stated as,
As the bond order increases, the stability also increases. The bond order is directly proportional to the bond energy and inversely proportional to the bond length.
To determine: The reason behind the increase in bond strength in case of
O2 and the decrease in the same in case of
N2 on the removal of an electron.
Q5: Label each chiral carbon in the following molecules as R or S. Make sure the stereocenter
to which each of your R/S assignments belong is perfectly clear to the grader. (8pts)
R
OCH 3
CI H
S
2pts for each R/S
HO
R
H
!!! I
OH
CI
HN
CI
R
H
Calculate the proton and carbon chemical shifts for this structure
A.
B.
b. Now consider the two bicyclic molecules A. and B. Note that A. is a dianion
and B. is a neutral molecule. One of these molecules is a highly reactive
compound first characterized in frozen noble gas matrices, that self-reacts
rapidly at temperatures above liquid nitrogen temperature. The other
compound was isolated at room temperature in the early 1960s, and is a
stable ligand used in organometallic chemistry. Which molecule is the more
stable molecule, and why?
Chapter 4 Solutions
Bundle: Chemistry: An Atoms First Approach, 2nd, Loose-Leaf + OWLv2, 4 terms (24 months) Printed Access Card
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Quantum Molecular Orbital Theory (PChem Lecture: LCAO and gerade ungerade orbitals); Author: Prof Melko;https://www.youtube.com/watch?v=l59CGEstSGU;License: Standard YouTube License, CC-BY