The structures of two compounds, Biacetyl and Acetoin, have been given. The Lewis structures for these compounds, the values for all C − C − O bond angles and the hybridization of the carbon atoms present in these compounds is to be predicted. The planar nature of the atoms present in biacetyl and the number of sigma and pi bonds present in both the given compounds is to be determined. Concept introduction: The hybridization of an atom can be obtained by finding its steric number. The sum of the numbers of atoms bonded to the required atom and the number of lone pairs the atom has is known as the steric number. If the steric number is 4 , the atom is sp 3 hybridized. If the steric number is 3 , the atom is sp 2 hybridized. If the steric number is 2 , the atom is sp hybridized. Sigma bonds are the single bonds present between atoms in a compound. The second bonding that occurs between the atoms is known as the pi bonding. To determine: The Lewis structure, the C − C − O bond angle value, hybridization of the carbon atoms and the number of sigma and pi bonds present in both the given compounds.
The structures of two compounds, Biacetyl and Acetoin, have been given. The Lewis structures for these compounds, the values for all C − C − O bond angles and the hybridization of the carbon atoms present in these compounds is to be predicted. The planar nature of the atoms present in biacetyl and the number of sigma and pi bonds present in both the given compounds is to be determined. Concept introduction: The hybridization of an atom can be obtained by finding its steric number. The sum of the numbers of atoms bonded to the required atom and the number of lone pairs the atom has is known as the steric number. If the steric number is 4 , the atom is sp 3 hybridized. If the steric number is 3 , the atom is sp 2 hybridized. If the steric number is 2 , the atom is sp hybridized. Sigma bonds are the single bonds present between atoms in a compound. The second bonding that occurs between the atoms is known as the pi bonding. To determine: The Lewis structure, the C − C − O bond angle value, hybridization of the carbon atoms and the number of sigma and pi bonds present in both the given compounds.
Solution Summary: The author explains the Lewis structures of two compounds, Biacetyl and Acetoin, and the number of sigma and pi bonds present in both the given compounds.
Interpretation: The structures of two compounds, Biacetyl and Acetoin, have been given. The Lewis structures for these compounds, the values for all
C−C−O bond angles and the hybridization of the carbon atoms present in these compounds is to be predicted. The planar nature of the atoms present in biacetyl and the number of sigma and pi bonds present in both the given compounds is to be determined.
Concept introduction: The hybridization of an atom can be obtained by finding its steric number. The sum of the numbers of atoms bonded to the required atom and the number of lone pairs the atom has is known as the steric number.
If the steric number is
4, the atom is
sp3 hybridized.
If the steric number is
3, the atom is
sp2 hybridized.
If the steric number is
2, the atom is
sp hybridized.
Sigma bonds are the single bonds present between atoms in a compound. The second bonding that occurs between the atoms is known as the pi bonding.
To determine: The Lewis structure, the
C−C−O bond angle value, hybridization of the carbon atoms and the number of sigma and pi bonds present in both the given compounds.
Denote the dipole for the indicated bonds in the following molecules.
H3C
✓
CH3
B
F-CCl 3
Br-Cl
H3C Si(CH3)3
wwwwwww
OH
НО.
HO
HO
OH
vitamin C
CH3
For the SN2 reaction, draw the major organic product and select the correct (R) or (S) designation around the stereocenter
carbon in the organic substrate and organic product. Include wedge-and-dash bonds and draw hydrogen on a stereocenter.
Η
1
D
EN
Select Draw Templates More
C
H
D
N
Erase
Q9: Explain why compound I is protonated on O while compound II is protonated on N.
NH2
NH2
I
II
Chapter 4 Solutions
Bundle: Chemistry: An Atoms First Approach, 2nd, Loose-Leaf + OWLv2, 4 terms (24 months) Printed Access Card
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.