COLLEGE PHYSICS
COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Chapter 4, Problem 61QAP
To determine

(a)

The force that the table exerts on box A if box B weighs 35N

Expert Solution
Check Mark

Answer to Problem 61QAP

The force exerted by table on box A is =45N and vertically upwards.

Explanation of Solution

Given:

  COLLEGE PHYSICS, Chapter 4, Problem 61QAP , additional homework tip  1

Box A weighs =80N

Box B weighs =35N

Pulley and rope are massless.

Formula Used:

  Fext,Ay=T+nwA=mAay=0=>n=wAT

Calculation:

The forces acting on Box A are the tension in the rope, the force due to gravity, and the force the table exerts on box A (also known as the normal force).

The tension in the rope is equal to the weight of box B when box B is at rest.

If the weight of box B is larger than the weight of box A, both boxes start to move-box A moves up, while box B moves down.

Free-body diagram of box A:

  COLLEGE PHYSICS, Chapter 4, Problem 61QAP , additional homework tip  2

If box A remains at rest, then

  Fext,Ay=T+nwA=mAay=0=>n=wAT

If box B weighs 35N, then the tension T=35N, since Box B remains at rest.

  =>n=wAT=(80N)(35N)=45N and points up

Conclusion:

The force that table exerts on box A if box B weighs 35N is =45N and points up.

To determine

(b)

The force that the table exerts on box A if box B weighs 70N

Expert Solution
Check Mark

Answer to Problem 61QAP

The force exerted by table on box A is =10N and vertically upwards.

Explanation of Solution

Given info:

  COLLEGE PHYSICS, Chapter 4, Problem 61QAP , additional homework tip  3

Box A weighs =80N

Box B weighs =70N

Pulley and rope are massless.

Formula Used:

  Fext,Ay=T+nwA=mAay=0=>n=wAT

Calculation:

The forces acting on Box A are the tension in the rope, the force due to gravity, and the force the table exerts on box A (also known as the normal force).

The tension in the rope is equal to the weight of box B when box B is at rest.

If the weight of box B is larger than the weight of box A, both boxes start to move-box A moves up, while box B moves down.

Free-body diagram of box A:

  COLLEGE PHYSICS, Chapter 4, Problem 61QAP , additional homework tip  4

If box A remains at rest, then

  Fext,Ay=T+nwA=mAay=0=>n=wAT

If box B weighs 70N, then the tension T=70N, since Box B remains at rest.

  =>n=wAT=(80N)(70N)=10N and points up

Conclusion:

The force that table exerts on box A if box B weighs 70N is =10N and points up.

To determine

(c)

The force that the table exerts on box A if box B weighs 90N

Expert Solution
Check Mark

Answer to Problem 61QAP

The force that table exerts on box A if box B weighs 90N is =0N.

Explanation of Solution

Given:

  COLLEGE PHYSICS, Chapter 4, Problem 61QAP , additional homework tip  5

Box A weighs =80N

Box B weighs =90N

Pulley and rope are massless.

Formula Used:

  Fext,Ay=T+nwA=mAay=0=>n=wAT

Calculation:

The forces acting on Box A are the tension in the rope, the force due to gravity, and the force the table exerts on box A (also known as the normal force).

The tension in the rope is equal to the weight of box B when box B is at rest.

If the weight of box B is larger than the weight of box A, both boxes start to move-box A moves up, while box B moves down.

.

Free-body diagram of box A:

  COLLEGE PHYSICS, Chapter 4, Problem 61QAP , additional homework tip  6

If box A remains at rest, then

  Fext,Ay=T+nwA=mAay=0=>n=wAT

If box B weighs more than box A, then we would expect box B to fall down and lift box A off

The table.

Since box A is no longer touching the table, the normal goes to 0.

Conclusion:

The force that table exerts on box A if box B weighs 90N is =0N, since box A is no longer touching the table, the normal goes to 0.

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Chapter 4 Solutions

COLLEGE PHYSICS

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